幾秒鐘後如何獲取MouseDown？

Question

假設我有一個按鈕，我想要以下行爲：

當我點擊按鈕時，它激發了一個事件 - 好的，這很容易。

現在，如果我點擊並等待，幾秒鐘後它會啓動另一個事件。例如彈出菜單...

該怎麼辦？

Answer 1

DispatcherTimer PopupTimer = new DispatcherTimer(); 

    PopupTimer.Tick += new EventHandler(PopupTimerTick); 
    PopupTimer.Interval = new TimeSpan(0, 0, 0, 0,5); 


    private void PopupTimerTick(object sender, EventArgs e) 
    { 
     if (Mouse.LeftButton == MouseButtonState.Pressed) 
     { 
      // If still pressed showing popup 
      ((Storyboard)Resources["ShowPopup"]).Begin(); 
      PopupTimer.Stop(); 
     } 
    } 

    private void ImageOnMouseDown(object sender, MouseButtonEventArgs e) 
    { 
     PopupTimer.Start(); 
     e.Handled = true; 
    } 

    private void ImageOnMouseUp(object sender, MouseButtonEventArgs e) 
    { 
     e.Handled = true; 

     if (Popup.IsOpen == false) 
     { 
      ((Storyboard)Resources["ShowPopup"]).Stop(); 
      // Here the operation that works on the click 
     } 
    } 

Answer 2

你在檢查MouseUp事件嗎？

如果用戶按住鼠標按鈕2秒鐘以顯示彈出式菜單，您說的是什麼？

我會做的是在MouseDown事件上創建一個單獨的線程，等待2秒鐘。如果MouseUp事件在到期前觸發，則不執行任何操作，否則請執行事件。

// This event will be used for tracking if the MouseUp has been received 
private System.Threading.AutoResetEvent _stopTrigger; 

private void OnMouseDown(object sender, MouseButtonEventArgs e) 
{ 
    if (this._stopTrigger == null) 
    { 
     this._stopTrigger = new System.Threading.AutoResetEvent(false); 
    } 

    Action popupProcess = new Action(this.ShowPopupAfterTime); 

    // Make the Popup process on a separate thread 
    popupProcess.BeginInvoke(null, null); 

} 

private void OnMouseUp(object sender, MouseButtonEventArgs e) 
{ 
    if (this._stopTrigger != null) 
    { 
     // Sends the signal to the ShowPopupAfterTime that it should NOT display the pop up 
     // IIt will make WaitOne return true and not go into the if statement 
     this._stopTrigger.Set(); 
    } 
} 

private void ShowPopupAfterTime() 
{ 
    // Will enter the if after 2 seconds 
    if (!this._stopTrigger.WaitOne(2000)) 
    { 
     // This means it has NOT be trigged thus I can display the popup 



     // DISPLAY POPUP 
     // DON"T FORGET you are on a different thread here, NOT UI thread. You will have to use the Dispatcher to get back 
     // to the UI thread to display the popup 
    } 
} 

Answer 3

查一查定時器（）和DispatcherTimer（）

Answer 4

我會使用線程這樣

private void mousedownEvent(object sender, MouseButtonEventArgs e) 
    { 
     //Fire off a thread which will do the waiting in the background 
     new Thread(delegate() 
      { 
       //Wait for 2 seconds 
       Thread.Sleep(2000); 

       //dump a dowork() method onto the main thread 
       this.Dispatcher.Invoke(System.Windows.Threading.DispatcherPriority.Normal, new Action(delegate() 
       { 
        doWork(sender); 
       })); 
       return; 
      }).Start(); 
    } 

    private void doWork(object sender) 
    { 
     //if the button is still pressed 
     if ((sender as UIElement).IsMouseOver && Mouse.LeftButton == MouseButtonState.Pressed) 
     { 
      //continue here 
     } 
    } 

它會檢查按下鼠標鍵，然後在2秒後再次檢查，而不會停止主要的應用程序線程。我wou't檢查按鈕被按下的整個時間所以這可能是也可能不是你

重要巴蒂爾

Answer 5

您可以在MouseDown事件和計時器滴答事件運行2秒定時檢查的內容需要。你可以停止你的計時器。