Oracle從衆多JOIN中選擇一對多返回重複項

Question

我正在學習Oracle SQL，並且遇到了與當前查詢有關的問題。我正在處理幾個VIEW，這些VIEW是一對多的關係。

我得到了LISTAGG查詢的工作，這很好。

現在，我增加了一對多VIEW_PHONE到我的查詢。

我試着看着樞軸，但我得到了一點失落。我發現這個查詢使用Max，Case並且它自己可以工作。當我爲合併

個人，企業和家庭電話號碼的電話Case語句，結果有重複技巧串。

這裏是輸出

之前添加VIEW_PHONE

1  John M. Doe JDOE 1:1, 2:2, 3:3, 4:4  

添加VIEW_PHONE內加入

1  John M. Doe  JDOE  111-111-1111, 222-222-2222, 333-333-3333, 1;1, 1:1, 1:1, 2:2,2:2,2:2, 3:3, 3:3, 3:3, 4:4,4:4,4:4 

我注意到，如果我改變內部連接語句PHONE.PHONE_TYPE（家庭之後'，'BUSINESS'，'CELL'）改爲PHONE.PHONE_TYPE（'HOME'），它只會給出一個技能字符串，而不是3.由於我正在嘗試獲取3個電話號碼，因此影響了我與第e VIEW_SKILL。

如何解決此查詢不重複技能字符串。謝謝..

SELECT PERSON.PERSON_ID, PERSON.FIRST_NAME, PERSON.MIDDLE_NAME, PERSON.LAST_NAME,  
     PERSON.USER_NAME, 
     max(case when PHONE_TYPE = 'HOME' then PHONE_NUMBER end) as HOME_PHONE, 
     max(case when PHONE_TYP= 'BUSINESS' then PHONE_NUMBER end) as BUSINESS_PHONE, 
     max(case when PHONE_TYP= 'CELL' then PHONE_NUMBER end) as CELL_PHONE, 
     LISTAGG(case when SKILLS.SKILL_DESC = '1' then '1:1' 
        when SKILLS.SKILL_DESC = '2' then '2:2' 
        when SKILLS.SKILL_DESC = '3' then '3:3' 
        when SKILLS.SKILL_DESC = '4' then '4:4' 
    when SKILL_DESC = 'ADMIN' AND PERSON.DEPT= 'DEPT1' then 'DEPT1:ADMIN' 
    when SKILL_DESC = 'ADMIN' AND PERSON.DEPT= 'DEPT2' then 'DEPT2:ADMIN' 
        else '' 
       end, ',') WITHIN GROUP (ORDER BY SKILLS.SKILL_SHORT_DESC) AS Speciality 
FROM VIEW_PERSON PERSON INNER JOIN 
    (SELECT DISTINCT PERSON_ID, PHONE_TYPE, PHONE_NUMBER FROM VIEW_PHONE 
    ) PHONE 
    ON PHONE.PERSON_ID = PERSON.PERSON_ID AND PHONE.PHONE_TYPE('HOME', 'BUSINESS', 'CELL') LEFT JOIN 
    (SELECT DISTINCT PERSON_ID, SKILL_SHORT_DESC 
     FROM EPERSON.VIEW_UDRMS_PERSON_SKILL 
    ) SKILLS 
    ON SKILLS.PERSON_ID = PERSON.PERSON_ID 
GROUP BY PERSON.PERSON_ID, PERSON.FIRST_NAME, PERSON.MIDDLE_NAME, PERSON.LAST_NAME, PERSON.USER_NAME 

Answer 1

你可能之前做一個早期聚集，即總的加入：

SELECT PERSON.PERSON_ID, 
    PERSON.FIRST_NAME, 
    PERSON.MIDDLE_NAME, 
    PERSON.LAST_NAME, 
    PERSON.USER_NAME, 

    PHONE.HOME_PHONE, 
    PHONE.BUSINESS_PHONE, 
    PHONE.CELL_PHONE, 

    SKILLS.Speciality 

FROM VIEW_PERSON PERSON 

INNER JOIN 
(
    SELECT PERSON_ID, 
     MAX(CASE WHEN PHONE_TYPE = 'HOME' THEN PHONE_NUMBER end) AS HOME_PHONE, 
     MAX(CASE WHEN PHONE_TYP= 'BUSINESS' THEN PHONE_NUMBER end) AS BUSINESS_PHONE, 
     MAX(CASE WHEN PHONE_TYP= 'CELL' THEN PHONE_NUMBER end) AS CELL_PHONE 
    FROM VIEW_PHONE 
) PHONE 
ON PHONE.PERSON_ID = PERSON.PERSON_ID 

LEFT JOIN 
(
    SELECT PERSON_ID, 
     LISTAGG(CASE 
       WHEN SKILL_DESC = '1' THEN '1:1' 
       WHEN SKILL_DESC = '2' THEN '2:2' 
       WHEN SKILL_DESC = '3' THEN '3:3' 
       WHEN SKILL_DESC = '4' THEN '4:4' 
       ELSE '' 
       end, ',') 
     WITHIN GROUP (ORDER BY SKILL_SHORT_DESC) AS Speciality 
    FROM EPERSON.VIEW_UDRMS_PERSON_SKILL 
    GROUP BY PERSON_ID 
) SKILLS 
ON SKILLS.PERSON_ID = PERSON.PERSON_ID 

這可能是更有效，也因爲行數是在連接前減少。

Answer 2

試試這個：

SELECT PERSON_ID, 
    FIRST_NAME, 
    MIDDLE_NAME, 
    LAST_NAME, 
    USER_NAME, 
    home, 
    business, 
    cell, 
    listagg(speciality,',') within GROUP(
ORDER BY 1) speciality 
FROM 
    (SELECT * FROM 
(
SELECT PERSON.PERSON_ID, PERSON.FIRST_NAME, PERSON.MIDDLE_NAME, PERSON.LAST_NAME,  
     PERSON.USER_NAME,phone_type, 
     PHONE_NUMBER, 
     case when SKILLS.SKILL_SHORT_DESC = '1' then '1:1' 
        when SKILLS.SKILL_SHORT_DESC = '2' then '2:2' 
        when SKILLS.SKILL_SHORT_DESC = '3' then '3:3' 
        when SKILLS.SKILL_SHORT_DESC = '4' then '4:4' 
    when SKILL_SHORT_DESC = 'ADMIN' AND PERSON.DEPT= 'DEPT1' then 'DEPT1:ADMIN' 
    when SKILL_SHORT_DESC = 'ADMIN' AND PERSON.DEPT= 'DEPT2' then 'DEPT2:ADMIN' 
        else '' 
       end AS Speciality 
FROM VIEW_PERSON PERSON INNER JOIN 
    (SELECT DISTINCT PERSON_ID, PHONE_TYPE, PHONE_NUMBER FROM VIEW_PHONE 
    ) PHONE 
    ON PHONE.PERSON_ID = PERSON.PERSON_ID AND PHONE.PHONE_TYPE in ('HOME', 'BUSINESS', 'CELL') LEFT JOIN 
    (SELECT DISTINCT PERSON_ID, SKILL_SHORT_DESC 
     FROM VIEW_UDRMS_PERSON_SKILL 
    ) SKILLS 
    ON SKILLS.PERSON_ID = PERSON.PERSON_ID 
) 
pivot (MAX(phone_number) FOR(phone_type) IN ('HOME' 
AS 
    HOME,'BUSINESS' 
AS 
    BUSINESS, 'CELL' 
AS 
    CELL))) group by PERSON_ID, FIRST_NAME, MIDDLE_NAME, LAST_NAME, USER_NAME, home, cell, business; 

給出：

1 guru   guru 111-111-1111 111-444-1111 111-333-1111 1:1,2:2,3:3 

用途 'PIVOT'。