在Python中隨機生成一個隨機生成的數字，可以隨時調用

Question

我想要做的是讓Python生成一個介於1和6之間的數字，然後將6添加到該數字中，然後將其提供給我結果，但我似乎無法弄清楚是如何使可調用該值，因此可以在遊戲過程中有漲有跌，這裏是我到目前爲止有：

import random 
import time 
Name = input("Before we get started lets get your character created, tell me what is your name?") 
print() 
print ("Welcome ",Name," to the adventure of a lifetime. The next thing you will need to do is sort out your character stats. This will require dice rolls which we will do within the game.") 
print() 

def skillroll(): 
    skillroll="" 

    while skillroll !="Y" and skillroll != "N": 
     skillroll = input("First we need to roll for your skill, would you like me to roll? Y/N") 

     if skillroll=="Y": 
      print("Rolling the dice..") 
      skill=random.randint(1,6) 
      time.sleep(2) 
      print("I rolled a", skill, " I will now add 6 to this so your skill is", skill+6) 
      skill=skill+6 
      print() 

    return skillroll 

skillroll() 

我只是不能看如何獲得最終答案，以便在遊戲中使用它。

我的一個朋友送我這個幫助 https://github.com/protocol7/python-koans/blob/master/python%202/koans/about_classes.py

但我只是不能看到這個關乎每一個答案，我就發現了＃2是不同的語言。

Answer 1

只需使用：

import random 
random.randrange(1, 7) 

得到任何數字1和6

您的代碼就變成了：

import random 
import time 

def skillroll(): 
    skillroll="" 
    while skillroll !="Y" and skillroll != "N": 
     skillroll = input("First we need to roll for your skill, would you like me to roll? Y/N") 
     if skillroll=="Y": 
      print("Rolling the dice..") 
      skill = random.randrange(1, 7) 
      time.sleep(2) 
      print("I rolled a ", skill, ". I will now add 6 to this so your skill is", skill+6, "\n") 
      skill=skill+6 
      return skillroll # What if N?? 

Name = input("Before we get started lets get your character created, tell me 
what is your name?") 
print ("\nWelcome ",Name," to the adventure of a lifetime. The next thing you 
will need to do is sort out your character stats. This will require dice 
rolls which we will do within the game.\n") 
skillroll()