我想迭代主arraylist中的所有項目。迭代ArrayList <Class>裏面那個類
輸出是迄今爲止我走了。至於你可以看到它不顯示A3,a3_1並提前a3_2
謝謝!
這裏是我的代碼:
addModel增加模型到對象內部Araylist。它是Model類的一個方法。
模型
public class Model {
String name;
String surname;
ArrayList<Model> arr = new ArrayList<Model>();
....//Constructor, getters,setters, toString\\
}
主要
public class Test{
public static void main(String[] args) {
ArrayList<Model> list = new ArrayList<Model>();
Model a= new Model("1", "1");
list.add(a);
Model a2 = new Model("2", "2");
list.add(a2);
Model a2_1 = new Model("2_1", "2_1");
a2.addModel(a2_1);
Model a2_2 = new Model("2_2", "2_2");
a2.addModel(a2_2);
Model a2_3 = new Model("2_3", "2_3");
a2.addModel(a2_3);
Model a3 = new Model("3", "3");
list.add(a3);
Model a3_1 = new Model("3_1", "3_1");
a3.addModel(a3_1);
Model a3_2 = new Model("3_2", "3_2");
a3.addModel(a3_2);
iterate(list,0,true);
System.out.println("\nEnd");
}
public static int iterate(ArrayList<Model> m, int i, boolean isNew){
System.out.println(m.get(i).toString());
if(!m.get(i).getArr().isEmpty()){
Model mx = m.get(i);
ArrayList<Model> nextArray=mx.getArr();
if(isNew)
return iterate(nextArray, 0,true);
else
return iterate(nextArray, i,false);
}
else{
return iterate(m, i+1,true);
}
}
}
輸出
{ name: 1 surname: 1}
{ name: 2 surname: 2}
Exception in thread "main"
{ name: 2_1 surname: 2_1}
{ name: 2_2 surname: 2_2}
{ name: 2_3 surname: 2_3}
java.lang.IndexOutOfBoundsException: Index: 3, Size: 3
謝謝!!!!那就是你救了我一天的答案! – trd3v3lop