2016-05-02 60 views
6

我將UIImageView以編程方式添加到UIScrollView中,並在imageView上添加輕擊手勢。它確切地識別輕擊事件4次,並在第四次崩潰時沒有任何明確的錯誤消息。這是在一個名爲FeaturedListingDetailVC控制器UITapGestureRecognizer在多次敲擊時崩潰

代碼:

let frame = CGRect(x: 0, y: 0, width: 128, height: 128) 
_iv = UIImageView(frame: frame) 
_iv.image = UIImage(named: "no_media")    
_iv.userInteractionEnabled = true 

tapGesture = UITapGestureRecognizer(target: self, action: #selector(initImagePopup(_:))) 
_iv.addGestureRecognizer(tapGesture) 

_iv.widthAnchor.constraintEqualToConstant(CGFloat.init(128)).active = true 
_iv.heightAnchor.constraintEqualToConstant(CGFloat.init(128)).active = true 
hrScroll.addSubview(_iv) 

功能叫上點擊:

@objc func initImagePopup(gesture: UITapGestureRecognizer) { 
    print("I am tapped!!!") 
} 

而且,我的方式加載我的目標的viewController (即FeaturedListingDetailVC)真的很重要,但我不知道爲什麼以及如何。因爲當我將我的目標視圖控制器推入UINavigationViewController時,它會在第一次敲擊時崩潰,否則當我通過演示viewController初始化目標VC時,它將在第四次敲擊時崩潰。在第一次輕觸

崩潰時初始化下面的代碼:

let storyboard = UIStoryboard(name: "Post", bundle: nil) 
let featuredVC = storyboard.instantiateViewControllerWithIdentifier("FeaturedListingDetailVC") as! FeaturedListingDetailVC 
self.vc?.navigationController!.pushViewController(featuredVC, animated: true) 

4日點擊崩潰時初始化下面的代碼:

let storyboard = UIStoryboard(name: "Post", bundle: nil) 
let featuredVC = storyboard.instantiateViewControllerWithIdentifier("FeaturedListingDetailVC") as! FeaturedListingDetailVC 
self.vc?.navigationController!.presentViewController(featuredVC, animated: true, completion: nil) 

回溯:

* thread #1: tid = 0x78c3e, 0x0000000106365553 UIKit\`-[UIViewController(UIKitManual) release] + 122, queue = 'com.apple.main-thread', stop reason = EXC_BAD_INSTRUCTION (code=EXC_I386_INVOP, subcode=0x0) 
    frame #0: 0x0000000106365553 UIKit\`-[UIViewController(UIKitManual) release] + 122 
    frame #1: 0xfffffffee7368160 
    frame #2: 0x0000000105bf72f3 UIKit\`-[UIViewController setChildModalViewController:] + 248 
    frame #3: 0x0000000105be853e UIKit\`-[UIViewController dealloc] + 1329 
    frame #4: 0x0000000105f48b31 UIKit\`_UIGestureRecognizerSendTargetActions + 162 
    frame #5: 0x0000000105f4519a UIKit\`_UIGestureRecognizerSendActions + 162 
    frame #6: 0x0000000105f43197 UIKit\`-[UIGestureRecognizer _updateGestureWithEvent:buttonEvent:] + 843 
    frame #7: 0x0000000105f4b655 UIKit\`___UIGestureRecognizerUpdate_block_invoke898 + 79 
    frame #8: 0x0000000105f4b4f3 UIKit\`_UIGestureRecognizerRemoveObjectsFromArrayAndApplyBlocks + 342 
    frame #9: 0x0000000105f38e75 UIKit\`_UIGestureRecognizerUpdate + 2634 
    frame #10: 0x0000000105ac548e UIKit\`-[UIWindow _sendGesturesForEvent:] + 1137 
    frame #11: 0x0000000105ac66c4 UIKit\`-[UIWindow sendEvent:] + 849 
    frame #12: 0x0000000105a71dc6 UIKit\`-[UIApplication sendEvent:] + 263 
    frame #13: 0x0000000105a4b553 UIKit\`_UIApplicationHandleEventQueue + 6660 
    frame #14: 0x00000001046f2301 CoreFoundation\`__CFRUNLOOP_IS_CALLING_OUT_TO_A_SOURCE0_PERFORM_FUNCTION__ + 17 
    frame #15: 0x00000001046e822c CoreFoundation\`__CFRunLoopDoSources0 + 556 
    frame #16: 0x00000001046e76e3 CoreFoundation\`__CFRunLoopRun + 867 
    frame #17: 0x00000001046e70f8 CoreFoundation\`CFRunLoopRunSpecific + 488 
    frame #18: 0x000000010bf6ead2 GraphicsServices\`GSEventRunModal + 161 
    frame #19: 0x0000000105a50f09 UIKit\`UIApplicationMain + 171 
    * frame #20: 0x0000000103e34b22 JaClassified\`main + 114 at AppDelegate.swift:5 
    frame #21: 0x000000010886b92d libdyld.dylib\`start + 1 
    frame #22: 0x000000010886b92d libdyld.dylib\`start + 1 
+0

你試過調試過嗎? 「崩潰」並不是真正的問題描述! – luk2302

+0

你可以發佈回溯? –

+0

確保在不再需要時刪除觀察者。它可能會崩潰,因爲您正在向不再存在的對象發送事件。 – Daniel

回答

3

聽起來很奇怪,我測試了很多你的代碼,並且沒有辦法,總是崩潰。

所以我只是試圖回調方法的改變名稱:

func didTapOnImagePopup(recognizer: UITapGestureRecognizer) {} 

和它的作品。

我真的不知道爲什麼,我可以找到任何合理的解釋。

我唯一能想到的就是應該存在一個名爲「initImagePopup」的內部函數..但這很奇怪。

我真的很好奇真正的解釋,如果有人知道它。

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啊!我無法想象這一點。它吃了我整整一天。謝謝@Luca – umair151

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我也沒有..但理解爲什麼會很有趣! –