GPA計算器始終返回0.0

-3

我的GPA計算器似乎無法正常工作。我輸入的任何值的組合將返回0.0的GPA。代碼在我的IDE中格式正確，但我不知道如何縮進這裏，對不起。GPA計算器始終返回0.0

def gpacalculator(grade,credit): 
    gradescore = 0 
    gradescore = int(gradescore) 
    if grade in ("A","Z"): 
     gradescore = 4*credit 
    elif grade == "B+": 
     gradescore = 3.5*credit 
    elif grade == "B": 
     gradescore = 3*credit 
    elif grade == "C+": 
     gradescore = 2.5*credit 
    elif grade == "C": 
     gradescore = 2*credit 
    elif grade == "D+": 
     gradescore = 1.5*credit 
    elif grade == "D": 
     gradescore = 1*credit 
    elif grade == "F": 
     gradescore = 0*credit 

    return gradescore 

subject = input("How many subjects would you like to calculate?") 
subject = int(subject) 
print("The different levels of grades are: Z, A, B+, B, C+, C, D+, D, F") 
a = 0 
a = int(a) 
for a in range(0,subject): 
    grade = str(input("What's your grade for subject number " + str(a+1) + "?")) 
    grade.upper() 
    credit = int(input("What's the number of credits for subject number " + str(a+1) + "?")) 

totalcredit = 0 
totalcredit - int(totalcredit) 
totalcredit+=credit 

totalgradescore = 0 
totalgradescore = int(totalgradescore) 
totalgradescore += gpacalculator(grade,credit) 

gpa = totalgradescore/totalcredit 
print("Your GPA is: ",gpa)

來源

2017-08-06 NewProgrammer

有一個錯字'totalcredit - INT（totalcredit）'，應該是'totalcredit = INT（totalcredit）'。之後，這是正常工作。 – Ofisora

修復代碼工作的縮進。然後想一想，當你總是將變量置零，然後添加一些東西時會發生什麼。 –

第一個錯誤是totalcredit - int(totalcredit)我得到完全擺脫它，因爲沒有必要使totalcredit爲int，如果你把它聲明等於0同爲變量totalgradescore和a。您遇到的下一個問題是grade.upper，您需要設置grade = grade.upper()。最後，您需要縮進credit到totalcredit的加法，並將您的返回值縮小爲totalgradescore，因爲您希望它們在循環中，因爲您要爲每個課程更改它們，並將它們的聲明移至for循環之前，因爲您不需要希望他們在每次迭代時重置。

最後的代碼應該是這個樣子：

def gpacalculator(grade,credit): 
    gradescore = 0 
    gradescore = int(gradescore) 
    if grade in ("A","Z"): 
     gradescore = 4*credit 
    elif grade == "B+": 
     gradescore = 3.5*credit 
    elif grade == "B": 
     gradescore = 3*credit 
    elif grade == "C+": 
     gradescore = 2.5*credit 
    elif grade == "C": 
     gradescore = 2*credit 
    elif grade == "D+": 
     gradescore = 1.5*credit 
    elif grade == "D": 
     gradescore = 1*credit 
    elif grade == "F": 
     gradescore = 0*credit 
    return gradescore 

subject = input("How many subjects would you like to calculate?") 
subject = int(subject) 
print("The different levels of grades are: Z, A, B+, B, C+, C, D+, D, F") 
totalgradescore = 0 
totalcredit = 0 

for a in range(subject): 
    grade = str(input("What's your grade for subject number " + str(a+1) + "?")) 
    grade = grade.upper() 
    credit = int(input("What's the number of credits for subject number " + str(a+1) + "?")) 
    totalcredit += credit 
    totalgradescore += gpacalculator(grade,credit) 

gpa = totalgradescore/totalcredit 
print("Your GPA is: ", gpa)

來源

2017-08-06 06:10:28

你的問題很簡單

string.upper（s）返回s的副本，但帶有轉換爲大寫小寫字母。

這意味着您必須將返回值賦給變量。如果您測試輸入大寫字母等級的程序，它可以正常工作。

因此，只要這一變化

for a in range(0,subject): 
    grade = str(input("What's your grade for subject number " + str(a+1) + "?")) 
    grade = grade.upper() 
    credit = int(input("What's the number of credits for subject number " + str(a+1) + "?"))

而只是作爲一個額外的小費，如果你指定一個文字數字，沒有小數點點變量，該變量的類型將是整數，則不需要在下一行轉換它。你有

來源

2017-08-06 06:06:04

謝謝！我的代碼現在可用。我想我過了一段時間沒有進行簡單的編程就生鏽了...... – NewProgrammer

Ofisora也是對的，那行代碼有一個錯字，它沒有對你的程序做任何無害的事情，因爲它是一個不必要的行。 –

GPA計算器始終返回0.0

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