如何存儲cookie以便與HttpClient進行後續連接

Question

我有以下代碼將登錄詳細信息發佈到網站。它的工作原理，但我怎麼能有會話cookie所以我不必再爲

編輯其他頁面登錄：更新的代碼

進口...

public class Login extends Activity { 
    Button bLogin; 
    EditText teUsername, tePassword; 
    CheckBox chbRememberPass; 

    HttpClient httpclient; 
    HttpResponse response; 

    @Override 
    protected void onCreate(Bundle savedInstanceState) { 
     // TODO Auto-generated method stub 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.login); 
     initialiseVars(); 
     httpclient = new DefaultHttpClient(); 

     bLogin.setOnClickListener(new View.OnClickListener() { 

      public void onClick(View v) { 
       checkLoginDetails(); 
       test0(); 
      } 
     }); 
    } 

    private void initialiseVars() { 
     bLogin = (Button) findViewById(R.id.bLogin); 
     teUsername = (EditText) findViewById(R.id.etUsername); 
     tePassword = (EditText) findViewById(R.id.etPassword); 
     chbRememberPass = (CheckBox) findViewById(R.id.chkRememberPass); 
    } 

    private void checkLoginDetails() { 


     HttpPost httppost = new HttpPost(
       "mywebsite/login.php"); 
     // Add your data 
     List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(5); 
     nameValuePairs.add(new BasicNameValuePair("username", "admin")); 
     nameValuePairs.add(new BasicNameValuePair("password", "pass")); 

     try { 
      httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); 
      Log.d("myapp", "works till here. 2"); 
      try { 
       ResponseHandler<String> responseHandler = new BasicResponseHandler(); 
       String responseBody = httpclient.execute(httppost, responseHandler); 

        Log.d("firstCon",responseBody); 

      } catch (ClientProtocolException e) { 
       e.printStackTrace(); 
      } catch (IOException e) { 
       e.printStackTrace(); 
      } 
     } catch (UnsupportedEncodingException e) { 
      e.printStackTrace(); 
     } 

    } 

    private void test0() { 

     HttpGet httppost = new HttpGet(
       "https://mywebsite/userSettings.php"); 

     try { 
      response = httpclient.execute(httppost); 
      //String responseBody = EntityUtils.toString(response.getEntity());   
      try { 
       Log.d("secondCon", test()); 

      } catch (Exception e) { 
       // TODO Auto-generated catch block 
       Log.d("seconderror", e.toString()); 
      } 


     } catch (ClientProtocolException e) { 
      e.printStackTrace(); 
     } catch (IOException e) { 
      e.printStackTrace(); 
     } 

    } 

    } 

} 

Answer 1

不是創建一個新的DefaultHttpClient，重新使用它。您的Cookie存儲在DefaultHttpCilent中，所以如果您繼續重複使用相同的實例，您的Cookie將自動爲您處理。