插入數據時的錯誤數據庫的數據庫，

Question

雖然插入數據到mysql數據庫我得到下面的錯誤，並且一些以前的問題的答案stackoverflow我把protected $fillable在我的模型文件，但仍然顯示錯誤。當我創建我的第一個條目表的接受沒有任何錯誤，但是當我正在做我的新條目其示值誤差

。

SQLSTATE[23000]: Integrity constraint violation: 1452 Cannot add or update a child row: a foreign key constraint fails (`app`.`articles`, CONSTRAINT `articles_ibfk_1` FOREIGN KEY (`article_id`) REFERENCES `users` (`id`)) (SQL: insert into `articles` (`article_head`, `article_body`) values (abkskfbasfbv, zbfvaksdvaskdvjsdc 
)) 

Article.php

<?php 

namespace App; 

use Illuminate\Database\Eloquent\Model; 

class Article extends Model 
{ 
    protected $fillable = [ 
     'article_head', 'article_body', 
    ]; 
    public $timestamps = false; 
} 

遷移文件

<?php 

use Illuminate\Database\Migrations\Migration; 
use Illuminate\Database\Schema\Blueprint; 

class CreateArticlesTable extends Migration { 

    /** 
    * Run the migrations. 
    * 
    * @return void 
    */ 
    public function up() 
    { 
     Schema::create('articles', function(Blueprint $table) 
     { 
      $table->increments('article_id'); 
      $table->string('article_head', 500); 
      $table->string('article_body', 10000); 
      $table->dateTime('created_on'); 
      $table->timestamps(); 
     }); 
    } 


    /** 
    * Reverse the migrations. 
    * 
    * @return void 
    */ 
    public function down() 
    { 
     Schema::drop('articles'); 
    } 

} 

2016_04_27_181606_add_foreign_keys_to_articles_table.php

<?php 

use Illuminate\Database\Migrations\Migration; 
use Illuminate\Database\Schema\Blueprint; 

class AddForeignKeysToArticlesTable extends Migration { 

    /** 
    * Run the migrations. 
    * 
    * @return void 
    */ 
    public function up() 
    { 
     Schema::table('articles', function(Blueprint $table) 
     { 
      $table->foreign('article_id', 'articles_ibfk_1')->references('id')->on('users')->onUpdate('RESTRICT')->onDelete('RESTRICT'); 
     }); 
    } 


    /** 
    * Reverse the migrations. 
    * 
    * @return void 
    */ 
    public function down() 
    { 
     Schema::table('articles', function(Blueprint $table) 
     { 
      $table->dropForeign('articles_ibfk_1'); 
     }); 
    } 

} 

Answer 1

它只是簡單的說就是對正在插入的表的用戶不存在，或者你是不是對錶的用戶文章中插入值表文章article_id的價值。裸記住，上表的用戶列的article_id的值取決於ID的值上表的用戶

Answer 2

將

protected $primaryKey = "article_id"; 

在您的文章模型。