2016-05-25 34 views
1

我需要一個正則表達式來獲得用戶只有關鍵字52,誰擁有的關鍵字52,53,但低於54不被用戶表結構MYSQL REGEXP查詢關鍵字列

CREATE TABLE `User` (
    `id` int NOT NULL AUTO_INCREMENT, 
    `first_name` varchar(100) NOT NULL, 
    `last_name` varchar(100) NOT NULL, 
    `keywords` text, 
    PRIMARY KEY (`id`) 
) ENGINE=InnoDB DEFAULT CHARSET=utf8; 

Sample record1: 100, Sam, Thompson, "50,51,52,53,54" 
Sample record2: 100, Wan, Thompson, "50,52,53" 
Sample record3: 100, Kan, Thompson, "53,52,50,54" 

50 = sports 
51 = cricket 
52 = soccer 
53 = baseball 
54 = tennis 

到目前爲止是這樣的查詢我想出了。它給記錄了所有3

SELECT * FROM `User` WHERE keywords REGEXP '[[:<:]]52,53,54[[:>:]]' 

回答

3

嘗試使用FIND_IN_SET()而不是一個複雜的正則表達式:

SELECT u.* 
FROM User 
WHERE text = '52' OR 
    (FIND_IN_SET('52', text) > 0 AND FIND_IN_SET('53', text) > 0 AND 
    FIND_IN_SET('54', text) = 0) 

說明:

WHERE text = '52' -- users who have keyword 52 and only this keyword 
WHERE FIND_IN_SET('52', text) > 0 AND FIND_IN_SET('53', text) > 0 AND 
    FIND_IN_SET('54', text) = 0 
        -- users who have keywords 52 and 53 but not 54 
1
SELECT * FROM `User` WHERE keywords RLIKE "^52$"; --only 52 
SELECT * FROM `User` WHERE keywords RLIKE "(.*(52|53)){2}" AND keywords not RLIKE "54"; -- users who have keywords 52 and 53 but not 54 

編輯:備案:第二個查詢應該真的是not rlike [[:<:]]54[[:>:]] ,正如在OP的最初想法中一樣,爲了防止匹配,比方說,154。

http://sqlfiddle.com/#!9/cdc530/13