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我想實現oAuth 1.0使用翻新獲取請求,但無法獲得響應。郵差的oAuth 1.0獲取請求翻新android
響應:
{
"1": {
"entity_id": "1",
"parent_id": "0",
"position": "0",
"level": "0",
"name": "Root Catalog"
},
"2": {
"entity_id": "2",
"parent_id": "1",
"position": "1",
"level": "1",
"name": "Default Category",
"is_active": "1"
}
}
我的界面:
@GET("/api/rest/categories/?")
@Headers({ "Content-Type: application/json"})
Call<ResponseBody> getProduct(@Field("oauth_consumer_key") String grantType,
@Field("oauth_token") String username,
@Field("oauth_signature_method") String sig,
@Field("oauth_timestamp") String timS,
@Field("oauth_nonce") String nonc,
@Field("oauth_version") String vers,
@Header("Authorization") String authorization);
方法調用:
私人無效callService(){
byte[] credentials = "CONSUMER_SECRETE:TOKEN_SECRETE".getBytes();
String basicAuth = "Basic " + Base64.getEncoder().encodeToString(credentials);
UserClient apiService = ApiClient.getClient().create(UserClient.class);
Call<ResponseBody> call = apiService.getProduct("CONSUMER_KEY","TOKEN_KEY","HMAC-SHA1","1502218838","RuH2FG","1.0",basicAuth);
call.enqueue(new Callback<ResponseBody>() {
@Override
public void onResponse(Call<ResponseBody>call, Response<ResponseBody> response) {
if (response.isSuccessful()){
if (response.isSuccessful()){
}else{
Toast.makeText(getApplicationContext(), "Failed", Toast.LENGTH_LONG).show();
}
}else{
//First Option of error handling..
switch(response.code()){
case 404:
Toast.makeText(getApplicationContext(),R.string.server_error404, Toast.LENGTH_SHORT).show();
break;
case 500:
Toast.makeText(getApplicationContext(),R.string.server_error500, Toast.LENGTH_SHORT).show();
break;
default:
Toast.makeText(getApplicationContext(),R.string.server_errorUnknow, Toast.LENGTH_SHORT).show();
}
}
}
@Override
public void onFailure(Call<ResponseBody>call, Throwable t) {
Toast.makeText(getApplicationContext(), t.getMessage(), Toast.LENGTH_LONG).show();
}
});
}
有什麼我也試過: Android OAuth Retrofit Access Token Request
,並嘗試其他類型的,但他們都沒有工作。
任何人都可以幫我解決這個問題嗎?我想通過改造來實現這一點。
你得到解決? –
請添加您的解決方案,我堅持認證1.0 api @SubinBabu –