如何選擇出現在一列更多次數的日期

Question

對於如：

表是

 
date      bill amount 
12/06/2013     200 
12/06/2013     920 
15/06/2013     300 

，輸出是

 
date     bill amount 
12/06/2013     1120 
15/06/2013     300 

Answer 1

通過使用組實現你的目標。

Answer 2

SELECT theDate, COUNT(theDate) AS NumOccurrences 

FROM someTable GROUP BY theDate 

HAVING (COUNT(theDate) > 1) 

Answer 3

這裏是SQLFiddle

SELECT date, SUM(billamount) 
    FROM tab1 GROUP BY date; 

Answer 4

sqlfiddle

select d as "date", 
     sum(amount) as "bill amount", 
     count(*) as "count" 
from T 
group by d 
having count(*) > 0 --change zero to occurrence number you wish 
order by d; 

sqlfiddle