2017-02-03 36 views
1

我遇到了使用codeigniter加入這兩個數據庫的問題,我嘗試過使用mysql並使用它。如何在codeigniter中的兩個數據庫之間加入

能有人可以將它轉換爲笨

這是我的代碼

SELECT DATE_FORMAT(FROM_UNIXTIME(ex.extime), '%Y-%m-%d') as `export_report`, u.username as `Username`, ex.qdesc as `Search_Performed`, 
       ex.to as `Number_of_records_exported`, ex.format as `Format` 
       FROM cone.users u 
       INNER JOIN igdata.export_status as ex 
       ON u.id = ex.uid 
       WHERE DATE_FORMAT(FROM_UNIXTIME(ex.extime), '%Y-%m-%d') = '{$dateToday}' 
       ORDER BY u.username ASC 

我也把這個在我的構造

回答

0

試試這個:

 $this->db->select("DATE_FORMAT(FROM_UNIXTIME(ex.extime), '%Y-%m-%d') as export_report, u.username as Username, ex.qdesc as Search_Performed, ex.to as Number_of_records_exported, ex.format as Format");  
     $this->db->from('cone.users u'); 
     $this->db->join('igdata.export_status as ex', 'u.id = ex.uid'); 
     $this->db->where("DATE_FORMAT(FROM_UNIXTIME(ex.extime), '%Y-%m-%d') = '$dateToday'"); 
     $this->db->order_by("u.username", "asc"); 
     $query = $this->db->get(); 
+0

謝謝@Danilo Bustos,它工作d就像一個魅力:)這就是我需要的。 – codeninja

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