拉出多個值,這可能是容易的,但我似乎無法得到它..繼承人所有代碼:從陣列陣列內從函數調用PHP
function logRequest($currIP){
include("include/opendb.php");
$gets = $_SERVER['QUERY_STRING'];
$posts = http_build_query($_POST);
$ref = $_SERVER['HTTP_REFERER'];
$agent = $_SERVER['HTTP_USER_AGENT'];
$date = date('Y-m-d H:i:s');
$rlookup = $_SERVER['REMOTE_HOST'];
$requestType = $_SERVER['REQUEST_METHOD'];
$languageset = $_SERVER['HTTP_ACCEPT_LANGUAGE'];
$key = "GSICHECKPOINT1";
$combinedVars = array("combinded" ,$date, $currIP, $ref, $agent, $rlookup, $requestType, $languageset, $gets, $posts);
$array[0] = $encryptID = base64_encode(mcrypt_encrypt(MCRYPT_RIJNDAEL_256, md5($key), $combinedVars, MCRYPT_MODE_CBC, md5(md5($key))));
$array[1] = $decryptID = rtrim(mcrypt_decrypt(MCRYPT_RIJNDAEL_256, md5($key), base64_decode($encryptID), MCRYPT_MODE_CBC, md5(md5($key))), "\0");
$query = "INSERT INTO loadAttempts (date, IP, ref, useragent, dnslookup, requestType, language, gets, posts) VALUES ('$date', '$currIP', '$ref', '$agent', '$rlookup','$requestType', '$languageset', '$gets', '$posts')";
$result = mysql_query($query);
return $array;
}
我要回兩個$ encryptID和$從函數中解密ID,所以我把它們放入一個數組中。 (是這樣錯了嗎?)
然後我試圖使用此代碼,這些返回的值提交到另一個功能:
if(in_array($_SERVER['REMOTE_ADDR'], $blockIP)){
// Log attempt to get here.
list($encryptID, $decryptID) = logRequest($currIP);
// Send user to blockpage.
blockPage($encryptID, $decryptID);
}else{
blah blah blah
我的問題是,當我拉着這些返回的值,該blockPage顯示的「陣「爲$ decryptID,我不知道我在哪裏搞錯了這些值的功能。當$ decrpytID數組已經不在創建者函數中時,如何顯示$ decrpytID數組中的每個項目?
謝謝!
你可以做一個var_dump或printr什麼logRequest($ currIP)返回?它可能會揭示什麼是錯誤的。 – MrGlass 2011-12-26 20:38:48