檢查用戶是否存在與mysqli不起作用

Question

$stmt = $db->prepare("SELECT * FROM user WHERE name='Steve Job'"); 
$stmt->execute(); 
if($stmt->num_rows){ 
    echo "1"; 
} 

它在我的ajax回調中返回空白。我已經調試了好幾個小時。

Answer 1

$stmt = $db->prepare("SELECT * FROM user WHERE name='Steve Job'"); 
$stmt->execute(); 
$stmt->store_result(); 
$numRows = $stmt->num_rows; 
if($numRows > 0){ 
    echo "1"; 
} 

您需要num_rows