我使用jQuery的樹從這裏https://github.com/pioz/jquery-tree#readmejQuery的樹(皮奧斯):樹犯規與餅乾
問題是渲染樹的,當我做一個cookie保存正確呈現。當它重新呈現它時,如果我不遵循放置有序列表的特定方式,代碼將無法正常工作。
我想最好看看這個演示代碼。
- 整個樹是開放
- 點擊3級箭頭展開(兩樹)
- 執行刷新
現在,第一棵樹正確呈現再次用cookies顯示之前打開的內容,但是第二個樹沒有顯示。我認爲這是因爲在第二天,我把沒有sublevels的那個放在帶有sublevels的那個之上(這就是所謂的「差異」)。
有沒有辦法調整代碼,以便它可以使用cookie正確呈現視圖,而不管我在任何子平面中的順序如何?
// Require jQuery
// Use jQuery.cookie if you want to restore the previous expansion of the tree
jQuery.fn.tree = function(options) {
// Setup default options
/** Avaiable options are:
* - open_char: defeault character to display on open node in tree
* - close_char: defeault character to display on close node in tree
* - default_expanded_paths_string: if no cookie found the tree will be expand with this paths string
**/
if(options === undefined || options === null)
options = {};
var open_char = options.open_char;
var close_char = options.close_char;
var default_expanded_paths_string = options.default_expanded_paths_string;
if(open_char === undefined || open_char === null)
open_char = '▼';
if(close_char === undefined || close_char === null)
close_char = '►';
if(default_expanded_paths_string === undefined || default_expanded_paths_string === null)
default_expanded_paths_string = '0';
// Get the expanded paths from the current state of tree
jQuery.fn.save_paths = function() {
var paths = [];
var path = [];
var open_nodes = jQuery(this).find('li span.open');
var last_depth = null;
for(var i = 0; i < open_nodes.length; i++) {
var depth = jQuery(open_nodes[i]).parents('ul').length-1;
if((last_depth == null && depth > 0) || (depth > last_depth && depth-last_depth > 1))
continue;
var pos = jQuery(open_nodes[i]).parent().prevAll().length;
if(last_depth == null) {
path = [pos];
} else if(depth < last_depth) {
paths.push(path.join('/'));
var diff = last_depth - depth;
path.splice(path.length-diff-1, diff+1);
path.push(pos);
} else if(depth == last_depth) {
paths.push(path.join('/'));
path.splice(path.length-1, 1);
path.push(pos);
} else if(depth > last_depth) {
path.push(pos);
}
last_depth = depth;
}
paths.push(path.join('/'));
try { jQuery.cookie(this.attr('class'), paths.join(',')); }
catch(e) {}
};
// This function expand the tree with 'path'
jQuery.fn.restore_paths = function() {
var paths_string = null;
try { paths_string = jQuery.cookie(this.attr('class')); }
catch(e) { paths_string = default_expanded_paths_string; }
if(paths_string === null || paths_string === undefined)
paths_string = default_expanded_paths_string;
var paths = paths_string.split(',');
for(var i = 0; i < paths.length; i++) {
var obj = jQuery(this);
var path = paths[i].split('/');
for(var j = 0; j < path.length; j++) {
obj = jQuery(obj.children('li').children('ul')[path[j]]);
obj.show();
obj.parent().children('span').attr('class', 'open');
obj.parent().children('span').html(open_char);
}
}
};
for(var i = 0; i < this.length; i++) {
if(this[i].tagName === 'UL') {
// Make a tree
jQuery(this[i]).find('li').has('ul').prepend('<span class="close" style="cursor:pointer;">' + close_char + '</span>');
jQuery(this[i]).find('ul').hide();
// Restore cookie expand path
jQuery(this[i]).restore_paths();
// Click event
jQuery(this[i]).find('span').live('click', {tree : this[i]}, function(e) {
if (jQuery(this).attr('class') == 'open') {
jQuery(this).parent().children('ul').hide('slow');
jQuery(this).attr('class', 'close');
jQuery(this).html(close_char);
} else if (jQuery(this).attr('class') == 'close') {
jQuery(this).parent().children('ul').show('slow');
jQuery(this).attr('class', 'open');
jQuery(this).html(open_char);
}
jQuery(e.data.tree).save_paths();
});
}
}
}
而不是通過比較整個「class」屬性來檢查類,你應該使用「.hasClass()」。否則,如果您需要爲這些元素添加*另一個*類,那麼事情根本不會起作用。 – Pointy 2011-04-03 22:32:46
此外,該jsbin頁面正常工作,據我所知。什麼是破碎的部分? – Pointy 2011-04-03 22:38:23