假設純粹的VBScript,「簡單」的答案是編寫一個bignum add和multiply,然後以這種方式計算答案。
從RosettaCode使用代碼,我創建了以下VeryLargeInteger類和Hex64函數說4702170486407730494是0x41417724EBA8953E
的64位十進制等效
Option Explicit
Class VeryLongInteger
'http://rosettacode.org/wiki/Long_Multiplication#Liberty_BASIC
Public Function MULTIPLY(Str_A, Str_B)
Dim signA, signB, sResult, Str_Shift, i, d, Str_T
signA = 1
If Left(Str_A,1) = "-" Then
Str_A = Mid(Str_A,2)
signA = -1
End If
signB = 1
If Left(Str_B,1) = "-" Then
Str_B = Mid(Str_B,2)
signB = -1
End If
sResult = vbNullString
Str_T = vbNullString
Str_shift = vbNullString
For i = Len(Str_A) To 1 Step -1
d = CInt(Mid(Str_A,i,1))
Str_T = MULTBYDIGIT(Str_B, d)
sResult = ADD(sResult, Str_T & Str_shift)
Str_shift = Str_shift & "0"
'print d, Str_T, sResult
Next
If signA * signB < 0 Then sResult = "-" + sResult
'print sResult
MULTIPLY = sResult
End Function
Private Function MULTBYDIGIT(Str_A, d)
Dim sResult, carry, i, a, c
'multiply Str_A by digit d
sResult = vbNullString
carry = 0
For i = Len(Str_A) To 1 Step -1
a = CInt(Mid(Str_A,i,1))
c = a * d + carry
carry = c \ 10
c = c Mod 10
'print a, c
sResult = CStr(c) & sResult
Next
If carry > 0 Then sResult = CStr(carry) & sResult
'print sResult
MULTBYDIGIT = sResult
End Function
Public Function ADD(Str_A, Str_B)
Dim L, sResult, carry, i, a, b, c
'add Str_A + Str_B, for now only positive
l = MAX(Len(Str_A), Len(Str_B))
Str_A=PAD(Str_A,l)
Str_B=PAD(Str_B,l)
sResult = vbNullString 'result
carry = 0
For i = l To 1 Step -1
a = CInt(Mid(Str_A,i,1))
b = CInt(Mid(Str_B,i,1))
c = a + b + carry
carry = Int(c/10)
c = c Mod 10
'print a, b, c
sResult = CStr(c) & sResult
Next
If carry>0 Then sResult = CStr(carry) & sResult
'print sResult
ADD = sResult
End Function
Private Function Max(a,b)
If a > b Then
Max = a
Else
Max = b
End If
End Function
Private Function pad(a,n) 'pad from right with 0 to length n
Dim sResult
sResult = a
While Len(sResult) < n
sResult = "0" & sResult
Wend
pad = sResult
End Function
End Class
Function Hex64(sHex)
Dim VLI
Set VLI = New VeryLongInteger
Dim Sixteen(16)
Sixteen(0) = "1"
Sixteen(1) = "16"
Sixteen(2) = VLI.MULTIPLY(Sixteen(1),"16")
Sixteen(3) = VLI.MULTIPLY(Sixteen(2),"16")
Sixteen(4) = VLI.MULTIPLY(Sixteen(3),"16")
Sixteen(5) = VLI.MULTIPLY(Sixteen(4),"16")
Sixteen(6) = VLI.MULTIPLY(Sixteen(5),"16")
Sixteen(7) = VLI.MULTIPLY(Sixteen(6),"16")
Sixteen(8) = VLI.MULTIPLY(Sixteen(7),"16")
Sixteen(9) = VLI.MULTIPLY(Sixteen(8),"16")
Sixteen(10) = VLI.MULTIPLY(Sixteen(9),"16")
Sixteen(11) = VLI.MULTIPLY(Sixteen(10),"16")
Sixteen(12) = VLI.MULTIPLY(Sixteen(11),"16")
Sixteen(13) = VLI.MULTIPLY(Sixteen(12),"16")
Sixteen(14) = VLI.MULTIPLY(Sixteen(13),"16")
Sixteen(15) = VLI.MULTIPLY(Sixteen(14),"16")
Dim theAnswer, i, theDigit, theMultiplier, thePower, aPower
theAnswer = "0"
aPower = 0
For i = Len(sHex) To 1 Step -1
theDigit = UCase(Mid(sHex,i,1))
theMultiplier = InStr("ABCDEF",theDigit)-1
thePower = Sixteen(aPower)
thePower = VLI.MULTIPLY(CStr(theMultiplier),thePower)
theAnswer = VLI.ADD(theAnswer,thePower)
aPower = aPower + 1
Next
Hex64 = theAnswer
End Function
WScript.Echo Hex64("41417724EBA8953E")
我想說的「享受」,但它已經超過六個月以來的原始發佈,所以你可能找到了另一種解決方案。一切都一樣,這很有趣。
LATER
其他方式做Hex64,如果你想避免16的權力的預計算的是:
Function Hex64b(sHex)
Dim VLI
Set VLI = New VeryLongInteger
Dim theAnswer, i, theDigit, theMultiplier, thePower, aPower
theAnswer = "0"
thePower = "1"
For i = Len(sHex) To 1 Step -1
theDigit = UCase(Mid(sHex,i,1))
theMultiplier = InStr("ABCDEF",theDigit)-1
theAnswer = VLI.ADD(theAnswer,VLI.MULTIPLY(thePower,theMultiplier))
thePower = VLI.MULTIPLY(thePower,"16")
Next
Hex64b = theAnswer
End Function