嘗試更新一個表與另一個表

我有一個總帳表與人相處以下三列不列入簡潔：嘗試更新一個表與另一個表

**gl_account id** | **gl_amount** | **GL_adjustmentAmount** 
    9500   |  NULL  |  NULL 
    ...   | ...   |  ...

我有不同的調整表從不同的列上面除了兩個：

**gl_account id** | **GL_adjustmentamount** 
    9500   |   289.84 
    9500   |   9.63 
    9500   |   13646.11 
    9500   |   835.31 
    9500   |   -210 
    9500   |   -1019.02 
    9500   |   -200

我需要更新總帳表包括所有7個新gl_adjustments但我t只包含289.84的值中的一個。

這是我的代碼。

UPDATE LedgerTable 
SET [GL_adjustmentamount] = adjust.GL_adjustmentamount 
FROM LedgerTable AS genLed 
    FULL OUTER JOIN AdjustmentTable AS adjust 
    ON genLed.gl_accountid = adjust.gl_accountid

來源

2016-07-25 Ace

您的預期結果是什麼？你是否想「總結」這些值？ – sgeddes

您是否希望在記帳表中的所有調整總數中有記錄？如果是這樣，你想聚集在一個cte /子查詢然後更新，否則，如果你想每調整一個記錄，你需要'INSERT'而不是''UPDATE'。 –

我正在使用sql 2008.我想最初在總帳中擁有每個GL_adjustedamount，但我認爲總和值將是BEST。 :) – Ace

案例1：更新只爲一個帳戶

，如果你想這對於只有一個帳戶，您可以使用此：

declare @AccountID INT 
set @AccountID = 9500 

update Ledger 
set  GL_adjustmentAmount = GL_adjustmentAmount + (select  SUM(a.GL_AdjustmentAmount) 
                from  Adjustment a 
                where  a.GL_AccountID = @AccountID) 
where GL_AccountID = @AccountID

你要知道，在accountId將不得不在這裏指定。

案例2：如果您希望這對所有賬戶工作（應該&更可能是這種情況），那麼你就需要一個更「廣義」查詢更新所有帳戶的

那種東西：

update Ledger 
set  GL_AdjustmentAmount = ISNULL(GL_AdjustmentAmount,0) + ISNULL(collatedAdjustments.adjustment, 0) 
from Ledger ledger 
inner join 
(select   a.GL_AccountID, 
       SUM(a.GL_AdjustmentAmount) as Adjustment 
from   Adjustment adjustments 
group by  adjustments.GL_accountID) as collated 
on    ledger.GL_accountID = collated.GL_accountID

下面是一些你可以測試這個對一些樣本數據：

CREATE TABLE Ledger(GL_AccountID int, GL_Amount int, GL_AdjustmentAmount int); 
CREATE TABLE Adjustment(GL_AccountID int, GL_AdjustmentAmount int); 

INSERT INTO Ledger(GL_AccountID,GL_Amount, GL_AdjustmentAmount) VALUES(9500, null, null); 
INSERT INTO Ledger(GL_AccountID,GL_Amount, GL_AdjustmentAmount) VALUES(9600, null, null); 
INSERT INTO Ledger(GL_AccountID,GL_Amount, GL_AdjustmentAmount) VALUES(9700, null, null); 
INSERT INTO Ledger(GL_AccountID,GL_Amount, GL_AdjustmentAmount) VALUES(9800, null, null); 

INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9500, 289.84); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9500, 9.63); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9500, 13646.11); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9500, 835.31); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9500, -210); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9500, -1019.02); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9500, -200); 

INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9600, 29.84); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9600, 29.63); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9600, 16646.11); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9600, 335.31); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9600, -1210); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9600, -2019.02); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9600, -1200); 

INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9700, 2239.02); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9700, 1400); 

INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9800, 4121.02); 
INSERT INTO Adjustment(GL_AccountID, GL_AdjustmentAmount) VALUES(9800, 1234);

該查詢還將以前的任何調整（在ledger表中）也納入公式中。

希望這有助於！

來源

2016-07-25 16:15:05

東西告訴我OP沒有通過帳戶ID。 – sgeddes

也許你想要包含'Ledger.GL_AdjustmentAmount'而不僅僅是替換它？即'設置GL_AdjustmentAmount = GL_AdjustmentAmount + ...' – Glenn

@Glenn這是一個很好的觀點。相應地更新了答案。 –

select * into LedgerTable 
from Adjustment Table

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2016-07-25 20:17:05 abcool

嘗試更新一個表與另一個表

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