PHP解碼JSON數組並插入到MYSQL數據庫

Question

我想創建一個解碼JSON數組並將其插入數據庫的PHP腳本。到目前爲止，我已經設法讓腳本插入數組中的第一行，沒有別的。

我需要添加什麼才能讓腳本插入數組中的所有行？

這裏的陣列，忽略 「清單」，我並不需要這些數據，但（這是相當大的）： json 這裏的腳本：

<?php 
$servername = "localhost"; 
$username = "root"; 
$password = ""; 

// Create connection 
$con = mysql_connect($servername, $username, $password); 

//select db 
$selected = mysql_select_db("ed",$con); 

$json_obj = file_get_contents("stations.json"); 

//convert to stdclass object 
$arr = json_decode($json_obj,true); 

//store the element values into variables 

$id = $arr[0]["id"]; 
$name = $arr[0]["name"]; 
$system_id = $arr[0]["system_id"]; 
$max_landing_pad_size = $arr[0]["max_landing_pad_size"]; 
$distance_to_star = $arr[0]["distance_to_star"]; 
$faction = $arr[0]["faction"]; 
$government = $arr[0]["government"]; 
$allegiance = $arr[0]["allegiance"]; 
$state = $arr[0]["state"]; 
$type = $arr[0]["type"]; 
$has_blackmarket = $arr[0]["has_blackmarket"]; 
$has_commodities = $arr[0]["has_commodities"]; 
$has_refuel = $arr[0]["has_refuel"]; 
$has_repair = $arr[0]["has_repair"]; 
$has_rearm = $arr[0]["has_rearm"]; 
$has_outfitting = $arr[0]["has_outfitting"]; 
$has_shipyard = $arr[0]["has_shipyard"]; 

//insert values into mysql database 
$sql="INSERT INTO stations (station_id, name, system_id, max_landing_pad_size, distance_to_star, faction, government, allegiance, state, type, has_blackmarket, has_commodities, has_refuel, has_repair, has_rearm, has_outfitting, has_shipyard) 
VALUES ('$id', '$name', '$system_id', '$max_landing_pad_size', '$distance_to_star', '$faction', '$government', '$allegiance', '$state', '$type', '$has_blackmarket', '$has_commodities', '$has_refuel', '$has_repair', '$has_rearm', '$has_outfitting', '$has_shipyard')"; 

if(!mysql_query($sql,$con)) //$con is mysql connection object 
{ 
    die('Error : ' . mysql_error()); 
} 
?> 

Answer 1

使用的foreach

$arr = json_decode($json_obj,true);//decode object 
foreach($arr as $ar){ 

      $id = $ar["id"]; 
      $name = $ar["name"]; 
      $system_id = $ar["system_id"]; 
      $max_landing_pad_size = $ar["max_landing_pad_size"]; 
      $distance_to_star = $ar["distance_to_star"]; 
      $faction = $ar["faction"]; 
      $government = $ar["government"]; 
      $allegiance = $ar["allegiance"]; 
      $state = $ar["state"]; 
      $type = $ar["type"]; 
      $has_blackmarket = $ar["has_blackmarket"]; 
      $has_commodities = $ar["has_commodities"]; 
      $has_refuel = $ar["has_refuel"]; 
      $has_repair = $ar["has_repair"]; 
      $has_rearm = $ar["has_rearm"]; 
      $has_outfitting = $ar["has_outfitting"]; 
      $has_shipyard = $ar["has_shipyard"]; 

      //insert values into mysql database 
      $sql="INSERT INTO stations (station_id, name, system_id, max_landing_pad_size, distance_to_star, faction, government, allegiance, state, type, has_blackmarket, has_commodities, has_refuel, has_repair, has_rearm, has_outfitting, has_shipyard) 
      VALUES ('$id', '$name', '$system_id', '$max_landing_pad_size', '$distance_to_star', '$faction', '$government', '$allegiance', '$state', '$type', '$has_blackmarket', '$has_commodities', '$has_refuel', '$has_repair', '$has_rearm', '$has_outfitting', '$has_shipyard')"; 

      if(!mysql_query($sql,$con)) //$con is mysql connection object 
      { 
       die('Error : ' . mysql_error()); 
      } 

} 

Answer 2

嘗試這個。

$arr = json_decode($json_obj,true); 

$sql = 'INSERT INTO stations (`'; 

$sql.= implode('`,`', array_keys($arr[0])); 

$sql.= '`) values (\''; 

$sql.= implode('\',\'', $arr[0] ); 

$sql.= '\')'; 

Answer 3

對於像這種情況下的大量數據，您只需要執行一次查詢，否則您將不必要地加載數據庫。對於這一點，你可以建立你的查詢與被插入的所有數據，然後執行它，就像這樣：

<?php 
$arr = json_decode($json_obj,true);//decode object 
$query = "INSERT into stations (station_id, name, system_id, max_landing_pad_size, distance_to_star, faction, government, allegiance, state, type, has_blackmarket, has_commodities, has_refuel, has_repair, has_rearm, has_outfitting, has_shipyard) values "; 
foreach($arr as $ar) {  
    $query .= "($ar['id'],$ar['name'],$ar['system_id'], 
       $ar['max_landing_pad_size'],$ar['distance_to_star'],$ar['faction'], 
       $ar['government'],$ar['allegiance'],$ar['state'], 
       $ar['type'],$ar['has_blackmarket'],$ar['has_commodities'], 
       $ar['has_refuel'],$ar['has_repair'],$ar['has_rearm'], 
       $ar['has_outfitting'],$ar['has_shipyard']),"; 
} 
$query = rtrim(",",$query); 
if(!mysql_query($query,$con)) //$con is mysql connection object 
{ 
    die('Error : ' . mysql_error()); 
} 

如果你想知道，你原來的代碼不工作，因爲你只是抓住了json的第一行（$ arr [0]）。您需要遍歷數據以獲取所有行。