0
這是動作url:http://localhost/carsdirectory/users/dashboard
。插入查詢不在蛋糕php
dashboad.ctp(我有選擇日提交併在此選擇字段IM取出從該日提交car_type和表名car_types數據)
<?php echo $this->Form->create('User', array('type' => 'file', 'action' => 'dashboard')); ?>
<label class="ls-details-label">Type</label>
<div class="ls-details-box">
<?php
foreach ($car_types as $car_type)
{
$car_type_new[$car_type['Car_type']['id']]=
$car_type['Car_type']['car_type'];
}
echo $this->Form->input('car_type',
array( 'label'=>false,
'options'=>$car_type_new,
'empty'=>' Select ',
'class'=>'styledselect_form_1'));
?>
</div>
<?php echo $this->Form->end(array('label' => 'Submit',
'name' => 'Submit',
'div' => array('class' => 'ls-submit')));?>
users_controller.php中(控制器)
class UsersController extends AppController{
var $name = "Users";
public function dashboard(){
$this->loadModel('Car_type'); // your Model name => Car_type
$this->set('car_types', $this->Car_type->find('all'));
if(!empty($this->data))
{
$this->loadModel('Car');
if($this->Car->save($this->data))
{
$this->Session->setFlash('Detail has Been Saved');
$this->redirect(array('action'=>'dashboard'));
}
else
{
$this->Session->setFlash('Detail could not save');
}
}
}
車.PHP(模型)
<?php
class Car extends appModel{
var $name = "Car";
}
?>
我想數據的插圖中(表car_type_id字段命名汽車),但我不是能夠做到這一點
所以plz幫助我
在此先感謝,維卡斯TYAGI
不要使用VAR。使用公共。 – cwallenpoole 2012-03-01 12:46:40
錯誤是什麼去'else'? – 2012-03-01 12:49:10
感謝您的回覆,我已經公開,但仍然在空值Car_type_id提交 – 2012-03-01 12:52:22