ORDER BY DAY無論是年或月

Question

你好，我有一個問題，我想通過一天命令他們顯示日期到現在什麼生日至上，爲前：我有

15/08/2013 00:00:00 
15/08/2013 00:00:00 
29/08/2012 00:00:00 
23/08/2012 00:00:00 
16/08/2012 00:00:00 
10/08/2012 00:00:00 

我希望它是

10/08/2012 00:00:00 
15/08/2013 00:00:00 
15/08/2013 00:00:00 
16/08/2012 00:00:00 
23/08/2012 00:00:00 
29/08/2012 00:00:00 

我寫道：

public DataTable BirtdayReport(DateTime d) 
{ 
    try 
    { 

     string query = "SELECT C.Class_Name as [כיתה], P.Person_First_Name as [שם פרטי], P.Person_Last_Name as [שם משפחה], P.Date_Of_Birth AS [תאריך לידה] "; 
     query += "FROM Person as P INNER JOIN Customer as C ON P.[Person _ID] = C.Person_ID WHERE MONTH(P.Date_Of_Birth)=Month(@d) ORDER BY (DAYOFMONTH(Person.Date_Of_Birth)) ;"; 

     OleDbCommand command = new OleDbCommand(); 
     command.CommandText = query; 
     command.Parameters.AddWithValue("@d", d); 
     DataTable dt = AdoHelper.ExecuteDataTable(command); 
     return dt; 

    } 
    catch (Exception ex) 
    { 
     throw ex; 
    } 
} 

但排序它不喜歡我想要的。 你能幫助我嗎？

Answer 1

select 
    col1, col2, col3, col4 
from 
(
SELECT 
    C.Class_Name as col1, 
    P.Person_First_Name as col2, 
    P.Person_Last_Name as col3, 
    P.Date_Of_Birth AS col4, 
    DAYOFMONTH(Person.Date_Of_Birth) as ordCol 
FROM 
    Person as P INNER JOIN 
    Customer as C 
     ON P.[Person _ID] = C.Person_ID 
WHERE 
    MONTH(P.Date_Of_Birth)=Month(@d) 
) tbl 
ORDER BY tbl.ordCol 

Answer 2

這是基於標準的SQL，但它應該是很容易根據你的SQL方言進行修改：

ORDER BY 
    CASE WHEN EXTRACT(MONTH FROM Date_Of_Birth) > EXTRACT(MONTH FROM CURRENT_DATE) 
     OR (EXTRACT(MONTH FROM Date_Of_Birth) = EXTRACT(MONTH FROM CURRENT_DATE) AND 
      EXTRACT( DAY FROM Date_Of_Birth)>= EXTRACT(DAY FROM CURRENT_DATE)) 
     THEN 0 
     ELSE 1 
    END, 
    EXTRACT(MONTH FROM Date_Of_Birth), EXTRACT(DAY FROM Date_Of_Birth)