我有一個MemoryStream代表一個zip文件。 這是流是如何創建的: var zipMemoryStream = new MemoryStream();
using (var zipPackage = Package.Open(zipMemoryStream, FileMode.CreateNew))
{
foreach (var file in files)
{
我對發送郵件這樣的代碼: Intent i = new Intent(Intent.ACTION_SEND);
i.setType("text/plain");
i.putExtra(Intent.EXTRA_EMAIL , new String[]{"[email protected]"});
i.putExtra(Intent.EXTRA_SUBJECT, "subject of ema