我試圖檢索所有沒有保留連接到某個「huisnummer」(housenumber)的房屋。 SELECT * FROM huis WHERE NOT EXISTS(select * FROM reservering WHERE reservering.huisnummer = huis.huisnummer)
,當我在我的本地主機的phpmyadmin執行的代碼我得到一個錯誤: Keyword
我有以下SQL: SELECT
M.*
FROM
(
SELECT MAX(counter) AS FirstUserDate, imdb_id, language, season, aufloesung, episode
FROM autofehlerserie
GROUP BY imdb_id, language
) foo