我不知道我在做什麼錯我的代碼在這裏得到一個遞歸帕卡爾的三角形在python中工作。任何幫助,懇請讚賞:) n = 5
def printPascal(n):
Pascal_List = []
if n == 0:
Pascal_List.append([1])
return Pascal_List
if n == 1:
Pasca
import java.util.*;
public class PascalFinal
{
public static void main()
{
Scanner f = new Scanner(System.in);
System.out.print("How many rows of Pascal's triangle do you want to print:
我發現一些代碼來獲得帕斯卡三角,而無需使用數組或nCr的在Java中,如下: int maxRows = 6;
int r, num;
for (int i = 0; i <= maxRows; i++)
{
num = 1;
r = i + 1;
//pre-spacing
for (int j = maxRows - i; j > 0; j--)
您好我正在Java中製作迭代帕斯卡三角形。到目前爲止,一切都很好,直到行數超過13爲止。輸出變得有缺陷。我一定在這裏做錯了,請幫忙。 IterativePascal: public class IterativePascal extends ErrorPascal implements Pascal {
private int n;
IterativePascal(int n)
我所做的楊輝三角的實現,但事情是錯了,因爲當col match { case row => ...}不正確的山坳與行相匹配: def main(args: Array[String]) {
println("Pascal's Triangle")
for (row <- 0 to 10) {
for (col <- 0 to row) {
val res: Int = pa
所以,我由於某種原因,代碼是給我的錯誤: TypeError: Can't convert 'int' object to str implicitly
它與線做: answer = answer + combination(row, column) + "\t"
這裏是我的代碼: def combination(n, k):
if k == 0 or k == n: