排序日期差異SQL

Question

我寫：

Select datediff(hh,getutcdate(), End_Date) as "Duration" 
from MasterTable 
order by Duration 

要獲得升序小時值的差異。我得到輸出，

 
Duration 
-------- 
    -259 
    -210 
     5 
     10 
     22 
     35 
     75 
    105 
    235 

但我想，排序必須根據正數和負數的小時值來完成。所以，我需要輸出爲：

 
Duration 
-------- 
     5 
     10 
     22 
     35 
     75 
    105 
    235 
    -259 
    -210 

是否有任何調整來做這樣的任務？提前致謝。

Answer 1

如果你想要的順序，你已經在問題中指出，它是所有正數的先升序，然後是負數的升序，它應該是：

Select datediff(hh,getutcdate(),End_Date) as "Duration" from MasterTable 
order by CASE WHEN Duration >= 0 THEN 0 ELSE 1 END,Duration 

Answer 2

理解，你需要的是忽略時間標誌：

嘗試使用ABS：

Select datediff(hh,getutcdate(),End_Date) as "Duration" from MasterTable order by ABS(Duration) 

Answer 3

試試這個，

Select Abs(datediff(hh,getutcdate(),End_Date)) as "Duration" from MasterTable order by Abs(Duration)