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我遇到的特殊問題是爲question 4.16b of Structure and Interpretation of Computer Programs創建解決方案。這裏的程序需要被創建,轉換擺脫名單上的外括號
(lambda (a b)
(define u 'u)
(define v 'v)
'e1))
分爲:
(lambda (a b)
(let ((u '*unassigned*)
(v '*unassigned*))
(set! u 'u)
(set! v 'v)
'e1))
我的做法(見下文)並沒有這樣做,而是將其轉換成:
(lambda (a b)
(let ((u *unassigned*)
(v *unassigned*))
((set! u 'u)
(set! v 'v))
('e1)))
這裏我們在(見下文)和其他機構(('e1)
以上)生成的sets!
列表中存在問題cons current-element rest-of-body
(請參閱低)。它們被添加到列表中,而我想將它們作爲單個語句,即(set! u 'u) (set! v 'v)
而不是((set! u 'u) (set! v 'v))
和'e1
而不是`('e1)。
步驟:
;; b. Write a procedure scan-out-defines that takes a procedure body and returns an
;; equivalent one that has no internal definitions, by making the transformation
;; described above.
(define (scan-out expr)
(let ((vars (cadr expr))
(body (cddr expr)))
(make-lambda vars
; loop over body,
; store all definition names and bodies of the defines
; once finished looping transform those into lets
; where the rest is added to the body
(let body-transform ((body-elements body)
(definition-names '())
(definition-bodies '())
(rest-of-body '()))
(if (null? body-elements)
(transform-define-into-let definition-names
definition-bodies
rest-of-body)
(let ((current-element (car body-elements)))
(if (tagged-list? current-element 'define)
(body-transform (cdr body-elements)
(cons (get-definition-name current-element)
definition-names)
(cons (get-definition-body current-element)
definition-bodies)
rest-of-body)
(body-transform (cdr body-elements)
definition-names
definition-bodies
(cons current-element rest-of-body)))))))))
(define (tagged-list? exp tag)
(if (pair? exp)
(eq? (car exp) tag)
false))
(define (get-definition-name expr)
(cadr expr))
(define (get-definition-body expr)
(caddr expr))
(define (transform-define-into-let vars vals rest-of-body)
(list (list 'let (make-unassigned-vars vars)
(make-sets vars vals)
rest-of-body)))
(define (make-unassigned-vars vars)
(let aux ((var-elements vars)
(unassigned-vars '()))
(if (null? var-elements)
unassigned-vars
(aux (cdr var-elements)
(cons (list (car var-elements) '*unassigned*) unassigned-vars)))))
(define (make-sets vars vals)
(let aux ((var-elements vars)
(val-elements vals)
(sets '()))
(if (null? var-elements)
sets
(aux (cdr var-elements)
(cdr val-elements)
(cons (list 'set! (car var-elements) (car val-elements)) sets)))))
(define (make-lambda parameters body)
(cons 'lambda (cons parameters body)))
; testing
(scan-out '(lambda (a b)
(define u 'u)
(define v 'v)
'e1))
; Should be transformed into:
; => (lambda (a b)
; (let ((u '*unassigned*)
; (v '*unassigned*))
; (set! u 'u)
; (set! v 'v)
; 'e1))
; But is transformed into:
; => (lambda (a b)
; (let ((u *unassigned*)
; (v *unassigned*))
; ((set! u (quote u))
; (set! v (quote v)))
; ((quote e1))))
我試過被壓扁,像這樣的列表:
(define (transform-define-into-let definition-names definition-bodies rest-of-body)
(list (list 'let (make-unassigned-vars definition-names)
(append* (make-sets definition-names definition-bodies))
(append* rest-of-body))))
但當時只有rest-of-body
被剝離外括號,make-sets
仍然是一個列表:例如,
(lambda (a b)
(let ((u *unassigned*)
(v *unassigned*))
((set! u 'u)
(set! v 'v))
'e1))
什麼是正確的擺脫方式o f外部括號?
如果有人能幫助我,這將不勝感激。
嗨Renzo!非常感謝!!! :D只改變'transform-define-into-let'就足夠了。注意'make-unassigned-vars'在你的答案中沒有改變。 ;) –
不客氣!請注意,'* unassigned *'之前有兩個單引號(''),否則您生成'(u * unassigned *)'而不是'(u'* unassigned *)''。 – Renzo
啊我現在看到了。下一次,我會用一個程序來代替我的眼睛,然後再說一些沒有改變的東西。顯然這個引用是一個身份運算符,它對自身進行評估(一次)([source](http://www.phyast.pitt.edu/~micheles/scheme/scheme8.html))。我沒有看到這就是爲什麼''''不會評價爲'a'(兩次認證)。 –