這是我的查詢..我怎樣才能解決這個選擇查詢
SELECT tcs.tutor_id AS tid, tcs.category_id AS cid, tcs.subject_id AS sid, GROUP_CONCAT(DISTINCT s.subjects SEPARATOR ', ') AS subjects,
t.tutor_name, t.tutor_code AS tcode, DATE_FORMAT(t.registration_date, '%b %D, %Y') AS date, t.qualification,
GROUP_CONCAT(DISTINCT o.option_name SEPARATOR ', ') AS tutor_option, timg.image_name AS img
FROM tutor_category_subject as tcs
INNER JOIN subject AS s ON tcs.subject_id = s.subject_id
INNER JOIN tutor_option AS toption ON toption.tutor_id = tcs.tutor_id
INNER JOIN options AS o ON toption.option_id = o.option_id
INNER JOIN tutors AS t ON tcs.tutor_id = t.tutor_id
LEFT JOIN tutor_images AS timg ON timg.tutor_id = tcs.tutor_id
WHERE s.subjects LIKE '%business%' AND timg.image_type = 'profile'
GROUP BY tcs.tutor_id;
此查詢工作正常。但有一個與TIMG的IMAGE_TYPE問題明杆。這是輔導員可能有他們的個人資料圖像和一些輔導員沒有配置文件圖像。但是我需要選擇所有具有這種條件的導師,即使他們的個人資料圖片不是。在這個查詢中,如果導師沒有選擇...的導師沒有個人資料圖片,那麼我該怎麼做呢?
任何意見,不勝感激。 謝謝