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我正在嘗試做一個凱撒密碼,並且我已經非常接近了。問題是我的輸出只打印出單個字母,而不是整行的加密行。 E是英語中使用最頻繁的字母,所以想法是找出E和輸入中最常用的字母之間的距離。然後把所有東西都轉移到那個距離。我是python的新手,所以我還不是很好。非常感謝!這裏是我到目前爲止的代碼:在輸入字符串中移位值
maximum_character = unciphered_text[0]
maximum_count = unciphered_text.count(unciphered_text[0])
for char in unciphered_text:
if char is not " ":
if unciphered_text.count(char) > maximum_count:
maximum_character = char
print("The most frequent character used is: ", maximum_character)
ASCII_maximum = maximum_character.lower()
ASCII_number = ord(ASCII_maximum)
print(ASCII_number)
shift_distance = ord('e')-ASCII_number
print("The shift distance is: ", shift_distance)
def caesar_cipher(unciphered_text, shift_distance):
ciphered_text = ""
for char in unciphered_text:
cipher_process = ord(char)+shift_distance
post_translation = chr(cipher_process)
ciphered_text += post_translation
return ciphered_text
answer = caesar_cipher(unciphered_text, shift_distance)
print(answer)
它的工作!非常感謝!我不知道touchy python是如何與它縮進的。你認爲我可以通過其他方式改進我的代碼嗎?還是按照原樣完成工作?再次感謝,真的。我很恐慌。 – Amaranthus