遊戲角色不會雙跳c＃

Question

我試圖創建一個統一的2D平臺遊戲，當我嘗試使角色雙跳時，它將無法工作。我想知道我能否得到任何幫助。

using UnityEngine; 
using System.Collections; 

public class Player : MonoBehaviour { 

    public float maxSpeed = 3; 
    public float speed = 50f; 
    public float jumpPower = 150f; 

    public bool grounded; 
    public bool canDoubleJump; 

    private Rigidbody2D rb2d; 
    private Animator anim; 

    void Start() 
    { 
     rb2d = gameObject.GetComponent<Rigidbody2D>(); 
     anim = gameObject.GetComponent<Animator>(); 
    } 


    void Update() 
    { 

     anim.SetBool("Grounded", grounded); 
     anim.SetFloat("Speed", Mathf.Abs(rb2d.velocity.x)); 

     if(Input.GetAxis("Horizontal") < -0.1f) 
     { 
      transform.localScale = new Vector3(-1, 1, 1); 
     } 

     if(Input.GetAxis("Horizontal") > 0.1f) 
     { 
      transform.localScale = new Vector3(1, 1, 1); 
     } 

     if(Input.GetButton("Jump")) 
     { 
      if(grounded) 
      { 
       rb2d.AddForce(Vector2.up * jumpPower); 
       canDoubleJump = true; 
      } 
      else 
      { 
       if (canDoubleJump) 
       { 
        canDoubleJump = false; 
        rb2d.velocity = new Vector2(rb2d.velocity.x, 0); 
        rb2d.AddForce(Vector2.up * jumpPower); 

       } 
      } 
     } 

    } 

    void FixedUpdate() 
    { 
     Vector3 easeVelocity = rb2d.velocity; 
     easeVelocity.y = rb2d.velocity.y; 
     easeVelocity.z = 0.0f; 
     easeVelocity.x *= 0.75f; 

     float h = Input.GetAxis("Horizontal"); 

     //fake friction/easing x speed 
     if(grounded) 
     { 
      rb2d.velocity = easeVelocity; 
     } 


     //moving player 
     rb2d.AddForce((Vector2.right * speed) * h); 

     //limiting speed 
     if(rb2d.velocity.x > maxSpeed) 
     { 
      rb2d.velocity = new Vector2(maxSpeed, rb2d.velocity.y); 
     } 

     if(rb2d.velocity.x < -maxSpeed) 
     { 
      rb2d.velocity = new Vector2(-maxSpeed, rb2d.velocity.y); 
     } 
    } 
} 

Answer 1

問題是，您正在檢查跳轉按鈕當前是否處於停機狀態。按下和釋放按鈕通常發生在多個框架上（即在按鈕按下期間Update()被調用多次）。

有兩種方法可以解決這個問題。

最簡單的（也可能是最好的）是使這種改變：

，直到它被釋放並再次按下

if(Input.GetButtonDown("Jump")) 

GetButtonDown只返回其中按鈕被按下的第一幀真實的，虛假的。

另一種是包含第二個變量，該變量阻止第二個塊的激活，直到釋放按鈕後。這不太理想，但是顯示了GetButtonDown幕後的情況。

var isButtonDown = false; 

Update() { 
     if(Input.GetButton("Jump")) 
     { 
      if(grounded) 
      { 
       rb2d.AddForce(Vector2.up * jumpPower); 
       canDoubleJump = true; 
       isButtonDown = true; 
      } 
      else if(!isButtonDown) 
      { 
       if (canDoubleJump) 
       { 
        canDoubleJump = false; 
        rb2d.velocity = new Vector2(rb2d.velocity.x, 0); 
        rb2d.AddForce(Vector2.up * jumpPower); 

       } 
      } 
     } 
     else { 
      isButtonDown = false; 
     } 
    } 

請注意，這並沒有解決雙跳能力通常包括的「脫落平臺並跳一次」。我會把這個作爲練習留給讀者。