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SciPy的我有四個功能,象徵性地與Sympy計算,然後lambdified:優化從sympy
deriv_log_s_1 = sym.lambdify((z, m_1, m_2, s_1, s_2), deriv_log_sym_s_1, modules=['numpy', 'sympy'])
deriv_log_s_2 = sym.lambdify((z, m_1, m_2, s_1, s_2), deriv_log_sym_s_2, modules=['numpy', 'sympy'])
deriv_log_m_1 = sym.lambdify((z, m_1, m_2, s_1, s_2), deriv_log_sym_m_1, modules=['numpy', 'sympy'])
deriv_log_m_2 = sym.lambdify((z, m_1, m_2, s_1, s_2), deriv_log_sym_m_2, modules=['numpy', 'sympy'])
從這些功能,我定義了一個成本函數進行優化:
def cost_function(x, *args):
m_1, m_2, s_1, s_2 = x
print(args[0])
T1 = np.sum([deriv_log_m_1(y, m_1, m_2, s_1, s_2) for y in args[0]])
T2 = np.sum([deriv_log_m_2(y, m_1, m_2, s_1, s_2) for y in args[0]])
T3 = np.sum([deriv_log_m_1(y, m_1, m_2, s_1, s_2) for y in args[0]])
T4 = np.sum([deriv_log_m_1(y, m_1, m_2, s_1, s_2) for y in args[0]])
return T1 + T2 + T3 + T4
我的功能cost_function
作品如預期的那樣:
a = 48.7161
b = 16.3156
c = 17.0882
d = 7.0556
z = [0.5, 1, 2, 1.2, 3]
test = cost_function(np.array([a, b, c, d]).astype(np.float32), z)
但是,當我嘗試優化我T:
from scipy.optimize import fmin_powell
res = fmin_powell(cost_function, x0=np.array([a, b, c, d], dtype=np.float32), args=(z,))
它提出了以下錯誤:
AttributeError: 'Float' object has no attribute 'sqrt'
我不明白爲什麼這樣的錯誤單獨出現作爲我cost_function
不會引發任何錯誤。
一般情況下,它是通過numpy的陣列lambdified功能是一個好主意。這將在下一個SymPy版本中自動完成(請參閱https://github.com/sympy/sympy/pull/11312)。 – asmeurer