如何從一組ID號碼中獲得變量的SUM？ PLSQL

Question

我在這裏的問題是，我有兩個表，

SQL> select * from paydata1; 

IDNO NAME      J  SALARY  PAYHR 
---- ------------------------- - ---------- ---------- 
1111 Ann French    S  75000   0 
2222 Robert Costa    H   0   45 
3333 Linda Ames    H   0   50 
4444 Scott Brooks    S  78000   0 
5555 Susan Ash     S  57000   0 
6666 James Smith    S  55000   0 
7777 Mary Jones    H   0   36 
8888 John Morse    H   0   39 

和

SQL> select * from paytran1; 

IDNO PRO HOURSWK 
---- --- ---------- 
1111 123   20 
1111 456   10 
1111 789   15 
2222 123   17 
2222 456   24 
2222 789   20 
3333 123   20 
3333 789   20 
4444 123   10 
4444 456   28 
4444 789   5 

IDNO PRO HOURSWK 
---- --- ---------- 
5555 456   40 
6666 456   44 
7777 456   30 
7777 789   15 
8888 123   10 
8888 456   25 
8888 789   5 

MY PL/SQL代碼在這裏：

SET SERVEROUTPUT ON 
DECLARE 
     v_idno paydata1.idno%TYPE; 
     v_name paydata1.name%TYPE; 
     v_jcode paydata1.jobcode%TYPE; 
     v_sal paydata1.salary%TYPE; 
     v_payh paydata1.payhr%TYPE; 
     v_hrsw paytran1.hourswk%TYPE; 
     CURSOR curse IS 
       SELECT paydata1.idno, name, jobcode, salary, payhr, hourswk 
       FROM paydata1, paytran1; 
BEGIN 
OPEN curse; 
FETCH curse INTO v_idno, v_name, v_jcode, v_sal, v_payh, v_hrsw; 
WHILE curse%ROWCOUNT < 9 AND curse%FOUND LOOP 
     IF v_jcode = 'S' THEN 
       v_sal := v_sal/52; 
       DBMS_OUTPUT.PUT_LINE(v_name || ': weekly salary is ' || v_sal); 

     ELSE 
       v_hrsw := sum(payhr) 
       v_sal := v_payh * v_hrsw; 
       DBMS_OUTPUT.PUT_LINE(v_name || ': overall pay is ' || v_sal); 
     END IF; 
    FETCH curse INTO v_idno, v_name, v_jcode, v_sal, v_payh, v_hrsw; 
END LOOP; 
CLOSE curse; 
END; 
/

SET SERVEROUTPUT OFF 

我需要能夠將僱員的工資分配到每小時的工資乘以工作時間（從第二張表中） 我的問題是，在第二張表中，工作小時數分成多個部分。我怎樣才能得到工作時間的總和，所以我可以把它放到我的變量'v_hrsw'中？

現在它只抓取它在paytran1.hourswk中找到的第一個號碼，用作v_hrsw。

謝謝你的幫助。

編輯：

結果看起來是這樣的......目前

Ann French: weekly salary is 1442.31 
Robert Costa: overall pay is 900 
Linda Ames: overall pay is 1000 
Scott Brooks: weekly salary is 1500 
Susan Ash: weekly salary is 1096.15 
James Smith: weekly salary is 1057.69 
Mary Jones: overall pay is 720 
John Morse: overall pay is 780 

但任何與 「整體薪酬」 有一個不正確的總數。

Answer 1

直接使用此查詢來獲取您的輸出。

select 
     d.name||(case when d.j='S' then ': Weekly salary is ' 
      when d.j='H' then ': overall pay is ' 
     end)||(case when d.J='S' then d.salary/52 
      when d.j='H' then sum(t.hourswk)*d.payhr 
     end) as output 
    from 
    paydata1 d inner join paytran1 t 
    on d.idno=t.idno 
    group by d.idno ,d.name,d.J,d.salary,d.payhr; 

所以，你可以更改爲2臺您的預計輸出，怎麼你的PL/SQL代碼

declare 
cursor curse is 
    select 
     d.name||(case when d.j='S' then ': Weekly salary is ' 
      when d.j='H' then ': overall pay is ' 
     end)||(case when d.J='S' then d.salary/52 
      when d.j='H' then sum(t.hourswk)*d.payhr 
     end) as output 
    from 
    paydata1 d inner join paytran1 t 
    on d.idno=t.idno 
    group by d.idno ,d.name,d.J,d.salary,d.payhr; 
    begin 
    for c1 in curse 
    loop 
    DBMS_OUTPUT.PUT_LINE(c1.output); 
end loop; 
end;