GROUP BY日期範圍

Question

CREATE TABLE `connectionLog` (
    `ID` int(11) NOT NULL AUTO_INCREMENT, 
    `serverTimeConnected` datetime NOT NULL, 
    `serverTimeDisconnected` datetime NOT NULL, 
    PRIMARY KEY (`ID`) 
); 

使用此查詢我得到serverTimeConnected在一小時內的所有ID。

SELECT HOUR(`serverTimeConnected`) as STUNDE, 
    count(`ID`) as HITS 
FROM `connectionLog` 
GROUP BY HOUR(`serverTimeConnected`) 

但我需要serverTimeConnected和serverTimeDisconnected之間的所有ID。

ID serverTimeConnected serverTimeDisconnected 
1 10:00:00   10:10:00  
2 10:00:00   11:10:00  
3 10:00:00   12:10:00 

我需要的結果 - 像

STUNDE HITS 
10,  3 
11,  2 
12,  1 

Answer 1

如何group_concat

SELECT HOUR(`serverTimeConnected`) as STUNDE, 
     count(`ID`) as HITS, 
     group_concat(id) as IDs 
FROM `connectionLog` 
GROUP BY HOUR(`serverTimeConnected`) 

Answer 2

更新：我發現這個解決方案

SELECT Stunden.ID, COUNT(Stunden.ID) as HITS FROM Stunden 
INNER JOIN connectionLog cl 
    ON (
    (ADDTIME(DATE_FORMAT(cl.serverTimeConnected,'%Y-%m-%d 00:00:00'),CONCAT(Stunden.ID,":00:00")) 
     BETWEEN cl.serverTimeConnected AND cl.serverTimeDisconnected) 
    OR 
     (ADDTIME(DATE_FORMAT(cl.serverTimedisConnected,'%Y-%m-%d 00:00:00'),CONCAT(Stunden.ID,":00:00")) 
     BETWEEN cl.serverTimeConnected AND cl.serverTimeDisconnected) 
    ) 

GROUP BY Stunden.ID 

http://sqlfiddle.com/#!2/6f3b0/11（更新）

表Stunden是可用的所有不同小時的列表。 一個簡單的INNER JOIN當小時在連接和斷開連接之間（看一天），讓我們找到我們搜索的匹配數。 然後Group by小時，我們匹配的權利HITS。

Answer 3

你可以去看一下TIMEDIFF

http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html#function_timediff