如何根據N來製作近似數字並接近現實？

Question

她是我的表：

// users 
+----+--------+------------+----------------+------------+ 
| id | name | reputation |  avatar  | visibility | 
+----+--------+------------+----------------+------------+ 
| 1 | John | 344  | er0942334r4... | 1   | 
| 2 | Peter | 65544  | 340ojfc343f... | 0   | 
+----+--------+------------+----------------+------------+ 

// posts 
+----+--------+------------+-----------+ 
| id | title | content | author_id | 
+----+--------+------------+-----------+ 
| 1 | title1 | content1 | 2   | 
| 2 | title2 | content2 | 1   | 
+----+--------+------------+-----------+ 

這裏是我的查詢：

SELECT p.*, 
     COALESCE(u.name,'NoName') as `name`, 
     u.reputation as `rep`, 
     COALESCE(u.avatar,'default') as avatar 
FROM posts p 
LEFT JOIN users u 
ON u.id = p.author_id AND u.visibility = 1 

這裏是當前輸出：

+----+--------+------------+-----------+--------+------+----------------+ 
| id | title | content | author_id | name | rep |  avatar  | 
+----+--------+------------+-----------+--------+------+----------------+ 
| 1 | title1 | content1 | 2   | NoName |  | default  | 
| 2 | title2 | content2 | 1   | John | 344 | er0942334r4... | 
+----+--------+------------+-----------+--------+------+----------------+ 

正如你看到的，rep列將在user.visibility = 1之內爲空。現在我想從users.reputation的實際值創建一個近似數字並接近實際，並將其設置在那裏。

因此，這裏是預期結果：

+----+--------+------------+-----------+--------+------+----------------+ 
| id | title | content | author_id | name | rep |  avatar  | 
+----+--------+------------+-----------+--------+------+----------------+ 
| 1 | title1 | content1 | 2   | NoName | +5k | default  | 
| 2 | title2 | content2 | 1   | John | 344 | er0942334r4... | 
+----+--------+------------+-----------+--------+------+----------------+ 

這裏是所有可能的情況下爲rep：

• 1
• +100
• +1k
• +5k
• +20k
• +100k

我怎麼能這樣做？

Answer 1

您需要重新構造查詢，將「可見性」邏輯移動到SELECT。

我不知道確切的邏輯是什麼rep，但這裏有一個例子：

SELECT p.*, 
     (CASE WHEN u.visibility = 1 THEN u.name ELSE 'NoName' END) as `name`, 
     (CASE WHEN u.visibility = 1 THEN CAST(u.reputation as VARCHAR) 
      WHEN rep < 100 THEN '1' 
      WHEN rep < 1000 THEN '+100' 
      . . . 
     END) as `rep`, 
     (CASE WHEN u.visibility = 1 THEN u.avatar ELSE 'default' END) as avatar 
FROM posts p LEFT JOIN 
    users u 
    ON u.id = p.author_id; 

這假定rep存儲爲表中的一個數字。但是，輸出的值需要是字符串。