我遇到了下面附加代碼的問題。本質上它會產生巨大的內存泄漏,但我無法看到它發生的位置。C++內存泄漏,在哪裏?
什麼代碼的作用是接收字符串,稱爲打印的陣列,包含數字(節點)由分離的「」(由節點的遞減數目排序),發現其他兼容打印(兼容裝置,其另一個字符串沒有重疊節點0,因爲每個打印都包含它),並且當所有節點都被覆蓋時,它會根據加權圖計算風險函數。最終它保留了風險最低的解決方案。
問題是你在圖片中看到的泄漏。我真的無法得到它的來源。
下面的代碼:
#include "Analyzer.h"
#define INFINITY 999999999
// functions prototypes
bool areFullyCompatible(int *, int, string);
bool contains(int *, int, int);
bool selectionComplete(int , int);
void extractNodes(string , int *, int &, int);
void addNodes(int *, int &, string);
Analyzer::Analyzer(Graph *graph, string *prints, int printsLen) {
this->graph = graph;
this->prints = prints;
this->printsLen = printsLen;
this->actualResult = new string[graph->nodesNum];
this->bestResult = new string[graph->nodesNum];
this->bestReSize = INFINITY;
this->bestRisk = INFINITY;
this-> actualSize = -1;
}
void Analyzer::getBestResult(int &size) {
for (int i = 0; i < bestReSize; i++)
cout << bestResult[i] << endl;
}
void Analyzer::analyze() {
// the number of selected paths is at most equal to the number of nodes
int maxSize = this->graph->nodesNum;
float totRisk;
int *actualNodes = new int[maxSize];
int nodesNum;
bool newCycle = true;
for (int i = 0; i < printsLen - 1; i++) {
for (int j = i + 1; j < printsLen; j++) {
// initializing the current selection
if (newCycle) {
newCycle = false;
nodesNum = 0;
extractNodes(prints[i], actualNodes, nodesNum, maxSize);
this->actualResult[0] = prints[i];
this->actualSize = 1;
}
// adding just fully compatible prints
if (areFullyCompatible(actualNodes, nodesNum, prints[j])) {
this->actualResult[actualSize] = prints[j];
actualSize++;
addNodes(actualNodes, nodesNum, prints[j]);
}
if (selectionComplete(nodesNum, maxSize)) {
// it means it's no more a possible best solution with the minimum number of paths
if (actualSize > bestReSize) {
break;
}
// calculating the risk associated to the current selection of prints
totRisk = calculateRisk();
// saving the best result
if (actualSize <= bestReSize && totRisk < bestRisk) {
bestReSize = actualSize;
bestRisk = totRisk;
for(int k=0;k<actualSize; k++)
bestResult[k] = actualResult[k];
}
}
}
newCycle = true;
}
}
float Analyzer::calculateRisk() {
float totRisk = 0;
int maxSize = graph->nodesNum;
int *nodes = new int[maxSize];
int nodesNum = 0;
for (int i = 0; i < actualSize; i++) {
extractNodes(this->actualResult[i], nodes, nodesNum, maxSize);
// now nodes containt all the nodes from the print but 0, so I add it (it's already counted but misses)
nodes[nodesNum-1] = 0;
// at this point I use the graph to calculate the risk
for (int i = 0; i < nodesNum - 1; i++) {
float add = this->graph->nodes[nodes[i]].edges[nodes[i+1]]->risk;
totRisk += this->graph->nodes[nodes[i]].edges[nodes[i+1]]->risk;
//cout << "connecting " << nodes[i] << " to " << nodes[i + 1] << " with risk " << add << endl;
}
}
delete nodes;
return totRisk;
}
// -------------- HELP FUNCTIONS--------------
bool areFullyCompatible(int *nodes, int nodesNum, string print) {
char *node;
char *dup;
int tmp;
bool flag = false;
dup = strdup(print.c_str());
node = strtok(dup, ",");
while (node != NULL && !flag)
{
tmp = atoi(node);
if (contains(nodes, nodesNum, tmp))
flag = true;
node = strtok(NULL, ",");
}
// flag signals whether an element in the print is already contained. If it is, there's no full compatibility
if (flag)
return false;
delete dup;
delete node;
return true;
}
// adds the new nodes to the list
void addNodes(int *nodes, int &nodesNum, string print) {
char *node;
char *dup;
int tmp;
// in this case I must add the new nodes to the list
dup = strdup(print.c_str());
node = strtok(dup, ",");
while (node != NULL)
{
tmp = atoi(node);
if (tmp != 0) {
nodes[nodesNum] = tmp;
nodesNum++;
}
node = strtok(NULL, ",");
}
delete dup;
delete node;
}
// verifies whether a node is already contained in the nodes list
bool contains(int *nodes, int nodesNum, int node) {
for (int i = 0; i < nodesNum; i++)
if (nodes[i] == node)
return true;
return false;
}
// verifies if there are no more nodes to be added to the list (0 excluded)
bool selectionComplete(int nodesNum, int maxSize) {
return nodesNum == (maxSize-1);
}
// extracts nodes from a print add adds them to the nodes list
void extractNodes(string print, int *nodes, int &nodesNum, int maxSize) {
char *node;
char *dup;
int idx = 0;
int tmp;
dup = strdup(print.c_str());
node = strtok(dup, ",");
while (node != NULL)
{
tmp = atoi(node);
// not adding 0 because every prints contains it
if (tmp != 0) {
nodes[idx] = tmp;
idx++;
}
node = strtok(NULL, ",");
}
delete dup;
delete node;
nodesNum = idx;
}
你應該使用一個工具來查找泄漏(valgrind,purify,....) – dlavila