我可以重現您的錯誤。 nls
函數缺少其中的參數data
。
m<-nls(y ~ b/(x^2)+a, start=list(a=a_start, b=b_start))
# Error in nls(y ~ b/(x^2) + a, start = list(a = a_start, b = b_start)) :
# parameters without starting value in 'data': y, x
現在數據df
被創建並傳遞給nls函數。請確保,I()
中的絕緣表達是預期的。
df <- data.frame(x = c(71.33, 74.98 , 80 , 85.35 , 90.03),
y = c(119.17, 107.73 , 99.72 , 75, 54.59))
a_start <- -39.5
b_start <- 800000
m <- nls(y ~ I(b/(x^2+a)), data = df, start=list(a=a_start, b=b_start))
summary(m)
# Formula: y ~ I(b/(x^2 + a))
#
# Parameters:
# Estimate Std. Error t value Pr(>|t|)
# a -1743.2 872.5 -1.998 0.1396
# b 412486.2 89981.4 4.584 0.0195 *
# ---
# Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
#
# Residual standard error: 9.103 on 3 degrees of freedom
#
# Number of iterations to convergence: 6
# Achieved convergence tolerance: 4.371e-06
閱讀公式手冊頁以瞭解絕緣表達式。
?formula
的formula
手冊頁說,
The^operator indicates crossing to the specified degree. For example (a+b+c)^2 is identical to (a+b+c)*(a+b+c) which in turn expands to a formula containing the main effects for a, b and c together with their second-order interactions
此外,它建議使用I()
防止公式運算符和算術運算符之間的模糊。
這裏爲來自公式手冊頁
avoid this confusion, the function I() can be used to bracket those portions of a model formula where the operators are used in their arithmetic sense. For example, in the formula y ~ a + I(b+c), the term b+c is to be interpreted as the sum of b and c.
的另一句名言也是這人頁是值得一讀
?AsIs
In function formula. There it is used to inhibit the interpretation of operators such as "+", "-", "*" and "^" as formula operators, so they are used as arithmetical operators. This is interpreted as a symbol by terms.formula.
Sathish所在,謝謝! – aSportsguy
是的,完美的,並且改變工作!我不是貿易程序員,所以我發現一些R文檔很難閱讀,或者在這裏尋找某些語法解決方案。 。 。 – aSportsguy