Oracle每天每分鐘查詢

Question

我想在oracle sql中編寫一個查詢，它在當前一天的每一分鐘返回一列。但我還是不知道，如何啓動:-(

min 
27.03.2014 00:00 
27.03.2014 00:01 
27.03.2014 00:02 
... 
27.03.2014 23:59 

感謝

Answer 1

我們可以用算術處理日期，以及簡單的CONNECT BY招行產生的氣流。

alter session set nls_date_format='dd-mon-yyyy hh24:mi' 
/

with cte as (select trunc(sysdate) as start_date from dual) 
select start_date + ((level-1)/(24*60)) as date_w_mins 
from cte 
connect by level <= (24*60) 
/

Answer 2

SELECT date + minute FROM 
(
SELECT TO_DATE('yyyy.mm.dd', '2014.03.27') date FROM DUAL 
CROSS JOIN 
( 
SELECT 0 minute FROM DUAL 
UNION ALL 
SELECT rownum r 
FROM DUAL 
CONNECT BY rownum <= 1439 
) T 
) TT 

Answer 3

可以使用numtodsinterval功能也很簡單：

SELECT to_char(TRUNC(sysdate)+ 
       numtodsinterval (level-1,'minute'),'dd.mm.yyyy hh24:mi') min 
FROM dual 
CONNECT BY LEVEL <= (24*60);