SELECT ID擁有最多ID的編號

擁有帶item_id和color_id的產品表。我試圖讓color_id與最非空的實例。SELECT ID擁有最多ID的編號

這種失敗：

SELECT color_id 
    FROM products 
WHERE item_id=1234 
GROUP BY item_id 
HAVING MAX(COUNT(color_id))

與

Invalid use of group function

這

SELECT color_id, COUNT(color_id) 
    FROM products 
WHERE item_id=1234 
GROUP BY item_id

color_id count 
1, 323 
2, 122 
3, 554

我正在尋找color_id 3，它具有最多的實例。

有沒有一種快速簡單的方法來獲得我想要的而沒有2個查詢？

來源

2013-01-10 a coder

SELECT color_id AS id, COUNT(color_id) AS count 
FROM products 
WHERE item_id = 1234 AND color_id IS NOT NULL 
GROUP BY color_id 
ORDER BY count DESC 
LIMIT 1;

這將爲您提供color_id和color_id上的計數，順序由count從最大到最小。我認爲這是你想要的。

爲您編輯...

SELECT color_id, COUNT(*) FROM products WHERE color_id = 3;

來源

2013-01-10 02:03:26

檢查我的編輯 - 我typoed在WHERE列。 –

您應該添加一個「限制1」來回答問題。 –

剛剛檢查出它的工作原理 - 謝謝。 –

SELECT color_id 
FROM 
    (
     SELECT color_id, COUNT(color_id) totalCount 
     FROM products 
     WHERE item_id = 1234 
     GROUP BY color_id 
    ) s 
HAVING totalCount = MAX(totalCount)

更新1

SELECT color_id, COUNT(color_id) totalCount 
FROM products 
WHERE item_id = 1234 
GROUP BY color_id 
HAVING COUNT(color_id) = 
(
    SELECT COUNT(color_id) totalCount 
    FROM products 
    WHERE item_id = 1234 
    GROUP BY color_id 
    ORDER BY totalCount DESC 
    LIMIT 1 
)

SQLFiddle Demo (having tie)

來源

2013-01-10 02:05:18

我很欣賞這個回覆。謝謝。 –

SELECT 
    color_id, 
    COUNT(color_id) AS occurances 
FROM so_test 
GROUP BY color_id 
ORDER BY occurances DESC 
LIMIT 0, 1

下面是一個簡單撥弄着一個基本的表格顯示它的工作：sql fiddle

來源

2013-01-10 02:13:16 drneel

SELECT ID擁有最多ID的編號

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