2016-09-04 42 views
0

我有低於我的表是從我的查詢結果,檢索多個數據並顯示到單行

Status |Tasks|Owner|Details 
------------------------------- 
OnGoing|test |test |2016-09-01 
        test a 
OnGoing|test |test |2016-09-02 
        test b 
OnGoing|test |test |2016-09-03 
        test c 

我希望發生的是,如果任務是像test和狀態就像是OnGoing它便會在下面詳細列單行顯示,

Status |Tasks|Owner|Details 
------------------------------- 
OnGoing|test |test |2016-09-01 
        test a 
        2016-09-02 
        test b 
        2016-09-03 
        test c 

我目前的查詢,

$sql="SELECT date, status, task, owner, details 
     FROM tracker 
     WHERE date BETWEEN '" . $date . "' AND '" . $date1 . "' 
     ORDER BY date, status"; 

這裏是我的表中的代碼,

echo "<table width='auto' cellpadding='1px' cellspacing='0px' border=1 align='center'> 
<tr> 
<th align='center' style='border:dotted 1px;' bgcolor='#66CC00'><font color='#FFFFFF'><strong>Status</strong></font></th> 
<th align='center' style='border:dotted 1px;' bgcolor='#66CC00'><font color='#FFFFFF'><strong>Tasks</strong></font></th> 
<th align='center' style='border:dotted 1px;' bgcolor='#66CC00'><font color='#FFFFFF'><strong>Owner/s</strong></font></th> 
<th align='center' style='border:dotted 1px;' bgcolor='#66CC00'><font color='#FFFFFF'><strong>Details</strong></font></th> 
</tr>"; 

while($result = mysql_fetch_array($myData)) 
{ 
{ 
$status = $result['status']; 
$status = str_replace("\r\n", "<br>", $status); 
$status = str_replace("\r", "<br>", $status); 
$status = str_replace("\n", "<br>", $status); 

$task = $result['task']; 
$task = str_replace("\r\n", "<br>", $task); 
$task = str_replace("\r", "<br>", $task); 
$task = str_replace("\n", "<br>", $task); 

$owner = $result['owner']; 
$owner = str_replace("\r\n", "<br>", $owner); 
$owner = str_replace("\r", "<br>", $owner); 
$owner = str_replace("\n", "<br>", $owner); 

$date = $result['date']; 
$date = str_replace("\r\n", "<br>", $date); 
$date = str_replace("\r", "<br>", $date); 
$date = str_replace("\n", "<br>", $date); 

$details = $result['details']; 
$details = str_replace("\r\n", "<br>", $details); 
$details = str_replace("\r", "<br>", $details); 
$details = str_replace("\n", "<br>", $details); 

echo "<form action='get_test.php' method='post'>"; 
echo"<tr>"; 
echo "<td align='center'>" . $result['status'] . "<input type=hidden name=status value=" . $result['status'] . " </td>"; 
echo "<td align='center'>" . $result['task'] . "<input type=hidden name=task value=" . $result['task'] . " </td>"; 
echo "<td align='center'>" . $result['owner'] . "<input type=hidden name=owner value=" . $result['owner'] . " </td>"; 
echo 
"<td align='left' width='auto'> 
" . $date . "<input type=hidden name=date value=" . htmlspecialchars($date) . " /><br> 
" . $details . "<input type=hidden name=details value=" . htmlspecialchars($details) . " /> </td>"; 
"</tr>"; 
echo "</form>"; 
} 
} 
echo "</table>"; 

回答

0

您可以嘗試group_concat,例如

select status, task, owner, group_concat(date, details order by date separator ' ') 
from tracker 
where date between '" . $date . "' and '" . $date1 . "' 
group by status, task, owner 
order by status 
+0

感謝您的幫助,但即時得到這個錯誤: '警告:mysql_fetch_array()預計參數1是資源,布爾在C中給出:行\ XAMPP \ htdocs中\跟蹤\ get_test.php 64' – testyummy

+0

這是一個不同的錯誤。最初,你不應該使用'mysql_ *'函數,因爲它們在PHP 7中被棄用和刪除。[''mysql_fetch_array'](http://php.net/manual/en/function.mysql-fetch-array.php)想把'mysql_query'的結果作爲它的第一個參數,但是你給它一個數組。 –

+0

對不起,但我是新來的這種編碼的東西...任何想法如何解決上述我的代碼給出的錯誤? – testyummy

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