打開包裝列表爲大熊貓

Question

鑑於我有一個名單，我怎麼能解開它變成一個熊貓的數據幀，例如：

data = {u'2344': ["id", "value1", "value2", "01", "Addf112", "Addf113", "02", " ", "Addf213"]} 

>> id value1 value2 
    01 Ad112 Ad113 
    02   Ad213 

Answer 1

你不得不提取列名的單個元素，然後構建一個列表包括2只列出了您的2行數據：

In [23]: 

data = {u'2344': ["id", "value1", "value2", "01", "Addf112", "Addf113", "02", " ", "Addf213"]} 

pd.DataFrame(columns = data['2344'][:3], data=[data['2344'][3:6], data['2344'][6:]]) 
Out[23]: 
    id value1 value2 
0 01 Addf112 Addf113 
1 02   Addf213 

的動態方法將是使用一個組塊（從答案之一修改，以此question）來構建字典並使用此構造DF ：

In [59]: 

def chunker(seq, stride): 
    cols = seq[:stride] 
    data = [seq[stride:][pos::stride] for pos in range(0, stride)] 
    return dict(zip(cols,data)) 

pd.DataFrame(chunker(data['2344'],3)) 

Out[59]: 
    id value1 value2 
0 01 Addf112 Addf113 
1 02   Addf213