2012-08-02 62 views
0

我正在創建一個電話簿程序,我可以在其中註冊並創建我自己的聯繫人列表。登錄後,該頁面將被導向到tabmain頁面,我可以在其中查看,添加,編輯或刪除聯繫人,以多選形式。無法將輸入變量傳遞給我的查詢

問題出在這裏:每當我點擊保存按鈕(功能displayNew中的按鈕),它應該獲得名和姓,然後查找數據庫是否匹配。如果沒有,那麼應該添加它們。現在,發生什麼是,我點擊保存按鈕後,沒有任何東西被傳遞給變量。

這裏是我的代碼:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> 
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> 
<head> 

<title>Tab-View Sample</title> 

<meta http-equiv="Content-Type" content="text/html;charset=utf-8" /> 
<meta name="description" content="" /> 
<meta name="keywords" content="" /> 

<link rel="stylesheet" type="text/css" href="css_collect/distribution/tab-view.css" /> 

</head> 
<body> 

<?php $id = isset($_GET['id']) ? $_GET['id'] : 1; ?> 
<?php 
    include 'conSql.php'; 
    session_start(); 
    $mySession = $_SESSION['user']; 

    //displays firsname and lastname of the user 
    $getNames = getNames($mySession); 
    $gET = explode("^", $getNames); 

    echo "Hi, "."<b>". $gET[0] ." ". $gET[1] ."</b>"."!"; 
    echo "</br>"; 
    echo "</br>"; 


?> 

    <div class="TabView" id="TabView"> 


    <!-- ***** Tabs ************************************************************ --> 

    <div class="Tabs" style="width: 452px;"> 
     <a <?=($id == 1) ? 'class="Current"' : 'href="sample.php?id=1"';?>>Contact List</a> 
     <a <?=($id == 2) ? 'class="Current"' : 'href="sample.php?id=2"';?>>Add contact</a> 
     <a <?=($id == 3) ? 'class="Current"' : 'href="sample.php?id=3"';?>>Edit/Delete</a> 
    </div> 


    <!-- ***** Pages *********************************************************** --> 

    <div class="Pages" style="width: 450px; height: 300px;"> 

     <div class="Page" style="display: <?=($id == 1) ? 'block' : 'none';?>"><div class="Pad"></div> 

      list of query 

     </div> 
     <div class="Page" style="display: <?=($id == 2) ? 'block' : 'none';?>"><div class="Pad"></div> 
      <Form Name ='' Method ='GET' action = 'tabmenu.php'> 
      <?php 
       displayNew(); 
       if(isset($_GET['btnAdd'])){ 
        $fname = $_GET['txtFname']; 
        $lname = $_GET['txtLname']; 

        // $s = "SELECT * "; 
        // $s .="FROM tbl_contactlist "; 
        // $s .="WHERE fname = '". $_GET['txtFname'] ."' and lname = '". $_GET['txtLname'] ."'"; 
        echo $s; 
       } 

      ?> 

     </div> 
     <div class="Page" style="display: <?=($id == 3) ? 'block' : 'none';?>"><div class="Pad"></div> 
      <?php 
       displayEdit(); 
      ?> 
     </div> 
    </div> 

    </div> 

    <script type="text/javascript" src="css_collect/distribution/tab-view.js"></script> 
    <script type="text/javascript"> 
    tabview_initialize('TabView'); 
    </script> 



    <?php 


    function getNames($mySession){ 
    //get the real name of the user (firstname and lastname) 
     $s = "SELECT * "; 
     $s .="FROM tbl_users "; 
     $s .="WHERE username = '". $mySession ."' ";   
     $rc = mysql_query($s); 

     $row = mysql_fetch_assoc($rc) or die(); 
     $details = $row["fname"]."^".$row["lname"]; 
     return $details; 
    } 
    function displayNew(){ 
     echo "<table border = '0'>"; 
     echo "<tr>"; 
     echo "<td colspan='2'><b>New Contact</b></td>"; 
     echo "</tr>"; 
     echo "<tr>"; 
     echo "<td colspan='2'>Please fill up the fields.</td>"; 
     echo "</tr>"; 
     echo "<tr>"; 
     echo "<td>First Name: </td>"; 
     echo "<td><input type='text' name='txtFname' id='txtFname'></td>"; 
     echo "</tr>"; 
     echo "<tr>"; 
     echo "<td>Last Name: </td>"; 
     echo "<td><input type='text' name='txtLname' id='txtLname'></td>"; 
     echo "</tr>"; 
     echo "<tr>"; 
     echo "<td>Nick Name: </td>"; 
     echo "<td><input type='text' name='txtNicname' id='txtNicname'></td>"; 
     echo "</tr>"; 
     echo "<tr>"; 
     echo "<td>Contact Number: </td>"; 
     echo "<td><input type='text' name='txtContactNum' id='txtContactNum'></td>"; 
     echo "</tr>"; 
     echo "<tr>"; 
     echo "<td></td>"; 
     echo "<td><input type='submit' name='btnAdd' id='btnAdd' value='SAVE'></td>"; 
     echo "</tr>"; 
     echo "</table>"; 
    } 
    function displayEdit(){ 
     echo "<table border = '0'>"; 
     echo "<tr>"; 
     echo "<td colspan='2'><b>Edit/Delete Page</b></td>"; 
     echo "</tr>"; 
     echo "<tr>"; 
     echo "<td colspan='2'>You can edit or delete:</td>"; 
     echo "</tr>"; 
     echo "<tr>"; 
     echo "<td>First Name: </td>"; 
     echo "<td><input type='text' name='txtFname' id='txtFname'></td>"; 
     echo "</tr>"; 
     echo "<tr>"; 
     echo "<td>Last Name: </td>"; 
     echo "<td><input type='text' name='txtLname' id='txtLname'></td>"; 
     echo "</tr>"; 
     echo "<tr>"; 
     echo "<td>Nick Name: </td>"; 
     echo "<td><input type='text' name='txtNicname' id='txtNicname'></td>"; 
     echo "</tr>"; 
     echo "<tr>"; 
     echo "<td>Contact Number: </td>"; 
     echo "<td><input type='text' name='txtContactNum' id='txtContactNum'></td>"; 
     echo "</tr>"; 
     echo "<tr>"; 
     echo "<td></td>"; 
     echo "<td><input type='submit' name='btnEdit' id='btnEdit' value='EDIT'>"; 
     echo "<input type='submit' name='btnDelete' id='btnDelete' value='DELETE'></td>"; 
     echo "</tr>"; 
     echo "<tr>"; 
     echo "<td></td>"; 
     echo "<td><input type='submit' name='btnCancel' id='btnCancel' value='Cancel'></td>"; 
     echo "</tr>"; 
     echo "</table>"; 
    } 
    function testMe(){ 
       echo "<script type='text/javascript'>\n"; 
       echo "alert('T E S T');\n"; 
       echo "</script>"; 
    } 


    ?> 
</body> 
</html> 
+0

你能刪除了一些「嘈雜」的代碼?只需發佈相關內容(即發佈的表單以及處理它的PHP代碼)。 – Matt 2012-08-02 14:38:51

+0

您必須調用session_start();在打印任何回顯,打印或html代碼之前,或者您將收到一個錯誤消息,說明標題已被髮送... – Oussama 2012-08-02 14:39:24

+1

您需要進行調試,當您遇到特定錯誤時,我們可以爲您提供幫助。 – Jocelyn 2012-08-02 14:39:27

回答

0

它看起來像你永遠不要關閉form標籤在HTML,這可能導致頁面無法做任何事情,當你點擊提交

+0

嗨。謝謝..這是問題,沒有在我的腳本結束..球員,抱歉的編碼和我的英語..我仍然是一個初學者在PHP中。我可以問一下怎樣或者什麼是正確的代碼輸入?我的意思是什麼是正確的編碼格式? – Lhynx 2012-08-03 14:26:05

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