如何在第一個查詢中選擇行但在第二個查詢中不存在？

Question

我有以下的MYSQL查詢，試圖選擇存在於查詢＃1但不存在於查詢＃2中的行，我嘗試使用NOT EXISTS，但該概念不適用於我的用例，我提供了樣本數據和結果，有沒有其他方法可以用於我的用例？我在尋找什麼？

SELECT 
    si.software_image_id, 
    si.software_image, 
    sib.software_image_build, 
    si.software_image_tag_id 
FROM software_product_builds spb 
INNER JOIN software_product_build_software_image_builds spbsib ON spb.software_product_build_id = spbsib.software_product_build_id 
INNER JOIN software_image_builds sib ON spbsib.software_image_build_id = sib.software_image_build_id 
INNER JOIN software_images si ON sib.software_image_id = si.software_image_id 
WHERE spb.software_product_build = 'CI_xxxx.LA.0.1-03291-STD.INT-7' and NOT EXISTS 

(SELECT 
    si.software_image_id, 
    si.software_image, 
    sib.software_image_build, 
    si.software_image_tag_id 
FROM software_product_builds spb 
INNER JOIN software_product_build_software_image_builds spbsib ON spb.software_product_build_id = spbsib.software_product_build_id 
INNER JOIN software_image_builds sib ON spbsib.software_image_build_id = sib.software_image_build_id 
INNER JOIN software_images si ON sib.software_image_id = si.software_image_id 
WHERE spb.software_product_build = 'CI_xxxx.LA.0.1-03291-STD.INT-6') 

查詢＃1結果

查詢＃2結果

預期的輸出： -

1781 BTFM.HW_NPR.1.1 BTFM.HW_NPR.1.1-00007-QCACHROM-1 2 

Answer 1

LEFT JOIN方法 - 慢

我從來沒有使用不存在方法之前，但也許如果你離開加入第二個查詢你的第一個查詢，得到的結果它僅出現在第一個查詢應該工作。我覺得是這樣的：

SELECT 
    query_1.* 
FROM 
    (SELECT 
     si.software_image_id, 
      si.software_image, 
      sib.software_image_build, 
      si.software_image_tag_id 
    FROM 
     software_product_builds spb 
    INNER JOIN software_product_build_software_image_builds spbsib ON spb.software_product_build_id = spbsib.software_product_build_id 
    INNER JOIN software_image_builds sib ON spbsib.software_image_build_id = sib.software_image_build_id 
    INNER JOIN software_images si ON sib.software_image_id = si.software_image_id 
    WHERE 
     spb.software_product_build = 'CI_xxxx.LA.0.1-03291-STD.INT-7') AS query_1 
     LEFT JOIN 
    (SELECT 
     si.software_image_id, 
      si.software_image, 
      sib.software_image_build, 
      si.software_image_tag_id 
    FROM 
     software_product_builds spb 
    INNER JOIN software_product_build_software_image_builds spbsib ON spb.software_product_build_id = spbsib.software_product_build_id 
    INNER JOIN software_image_builds sib ON spbsib.software_image_build_id = sib.software_image_build_id 
    INNER JOIN software_images si ON sib.software_image_id = si.software_image_id 
    WHERE 
     spb.software_product_build = 'CI_xxxx.LA.0.1-03291-STD.INT-6') AS query_2 ON query_1.software_image_build = query_2.software_image_build 
WHERE 
    query_2.software_image_build IS NULL 

假設software_product_build是要測試對

NOT IN的方法獨特的領域 - 慢

如果不加入不好的表現，你可以做一個簡單的字段是不是在第二個查詢如：

SELECT 
    si.software_image_id, 
    si.software_image, 
    sib.software_image_build, 
    si.software_image_tag_id 
FROM 
    software_product_builds spb 
     INNER JOIN 
    software_product_build_software_image_builds spbsib ON spb.software_product_build_id = spbsib.software_product_build_id 
     INNER JOIN 
    software_image_builds sib ON spbsib.software_image_build_id = sib.software_image_build_id 
     INNER JOIN 
    software_images si ON sib.software_image_id = si.software_image_id 
WHERE 
    spb.software_product_build = 'CI_xxxx.LA.0.1-03291-STD.INT-7' 
     AND sib.software_image_build NOT IN (SELECT 
      sib.software_image_build 
     FROM 
      software_product_builds spb 
       INNER JOIN 
      software_product_build_software_image_builds spbsib ON spb.software_product_build_id = spbsib.software_product_build_id 
       INNER JOIN 
      software_image_builds sib ON spbsib.software_image_build_id = sib.software_image_build_id 
       INNER JOIN 
      software_images si ON sib.software_image_id = si.software_image_id 
     WHERE 
      spb.software_product_build = 'CI_xxxx.LA.0.1-03291-STD.INT-6') 

無論哪種方式，你仍然需要d確定你的唯一標識符是什麼，這樣你可以檢查它不存在於第二個查詢中（就像@shadow指出的那樣）。 SQL如何知道匹配檢查不存在？ SQL需要確切地知道它匹配的是什麼。即使您需要通過連接他們像檢查字段的組合：

WHERE CONCAT(si.software_image, sib.software_image_build,) NOT IN (SELECT CONCAT(si.software_image,sib.software_image_build) FROM ......., 

最後更新，NOT EXISTS方法 - 最佳性能

上陰影的後面評論我已經找到NOT EXISTS方法性能要好得多。因此，請嘗試：

SELECT 
    si.software_image_id, 
    si.software_image, 
    sib.software_image_build, 
    si.software_image_tag_id 
FROM 
    software_product_builds spb 
     INNER JOIN 
    software_product_build_software_image_builds spbsib ON spb.software_product_build_id = spbsib.software_product_build_id 
     INNER JOIN 
    software_image_builds sib ON spbsib.software_image_build_id = sib.software_image_build_id 
     INNER JOIN 
    software_images si ON sib.software_image_id = si.software_image_id 
WHERE 
    spb.software_product_build = 'CI_xxxx.LA.0.1-03291-STD.INT-7' 
     AND NOT EXISTS(SELECT 
      * 
     FROM 
      software_product_builds spb_two 
       INNER JOIN 
      software_product_build_software_image_builds spbsib_two ON spb_two.software_product_build_id = spbsib_two.software_product_build_id 
       INNER JOIN 
      software_image_builds sib_two ON spbsib_two.software_image_build_id = sib_two.software_image_build_id 
       INNER JOIN 
      software_images si_two ON sib_two.software_image_id = si_two.software_image_id 
     WHERE 
      spb_two.software_product_build = 'CI_xxxx.LA.0.1-03291-STD.INT-6' 
       AND sib_two.software_image_id = sib.software_image_id)