如何創建一個十字交叉的對角矩陣

Question

如何創建這樣

A = [a 0 0 0 0 b; 
    0 a 0 0 b 0; 
    0 0 a b 0 0; 
    0 0 b a 0 0; 
    0 b 0 0 a 0; 
    b 0 0 0 0 a] 

Answer 1

矩陣也許是這樣的

N = 6; % Size of matrix 
a = 1; % Example value 
b = 2; % Example value 

A = a*eye(N) + b*fliplr(eye(N)); 

A = 
    1  0  0  0  0  2 
    0  1  0  0  2  0 
    0  0  1  2  0  0 
    0  0  2  1  0  0 
    0  2  0  0  1  0 
    2  0  0  0  0  1