PHP JSON編碼

我試圖生成以下JSON數據：從PHP foreach循環看起來像這樣內PHP JSON編碼

[ 
    { 
     "ID": "A1000", 
     "name": "John Simpson", 
     "serialID": "S41234", 
     "tagID": "ABC6456" 
    }, 
    { 
     "ID": "B2000", 
     "name": "Sally Smith", 
     "serialID": "B5134536", 
     "tagID": "KJJ451345" 
    }, 
    { 
     "ID": "A9854", 
     "name": "Henry Jones", 
     "serialID": "KY4239582309", 
     "tagID": "HYG452435" 
    } 
]

：

foreach($records as $record) { 

     $ID = $record->getField('propertyID'); 
     $name = $record->getField('assignedName'); 
     $serialID = $record->getField('serial'); 
     $tagID = $record->getField('tag'); 

    }

我已經嘗試使用：

$arr = array('ID' => $ID, 'name' => $name, 'serialID' => $serialID, 'tagID' => $tagID);

它適用於循環內的每個記錄，但不能計算出連接的語法t一起擺成一個單一的JSON數據字符串？

來源

2017-09-15 user982124

不會覆蓋'$ arr'每次迭代中，只需添加'[]' – Ghost

問題： -你有過寫你$arr變量中foreach()每個時間loop.That導致問題。

解決方案： -，而不是通過寫作，賦值數組象下面這樣： -

$arr = []; //create empty array 

foreach($records as $record) { 

    $arr[] = array(
       'ID' => $record->getField('propertyID'); 
       'name' => $record->getField('assignedName'); 
       'serialID' => $record->getField('serial'); 
       'tagID' => $record->getField('tag') 
      );//assign each sub-array to the newly created array 
} 
echo json_encode($arr);

來源

2017-09-15 06:58:07

精確，很好的解決方案.. +1 –

@SahilGulati感謝。欣賞它。 –

記錄添加到某種聚集陣列，然後json_encode它：

$items = []; 
foreach($records as $record) { 
    $items[] = [ 
     'ID' => $record->getField('propertyID'), 
     'name' = $record->getField('assignedName'), 
     'serialID' => $record->getField('serial'), 
     'tagID' => $record->getField('tag'), 
    ]; 
} 

echo json_encode($items);

來源

2017-09-15 06:57:57

試試這個：

$data= array(); 
foreach($records as $record) { 

$data[] = array(
     'ID' => $record->getField('propertyID'); 
     'name' => $record->getField('assignedName'); 
     'serialID' => $record->getField('serial'); 
     'tagID' => $record->getField('tag') 
     ); 
    } 

echo json_encode($data);

說明：製造陣列，把所有的數值放在它們的數字索引之一的循環中，json_enccode()它。

來源

2017-09-15 06:58:28

您可以使用類似array_map()此：

$result = array_map(function ($record) { 
    return [ 
     'ID'  => $record->getField('propertyID'), 
     'name'  => $record->getField('assignedName'), 
     'serialID' => $record->getField('serial'), 
     'tagID' => $record->getField('tag'), 
    ]; 
}, $records); 

echo json_encode($result);

希望這有助於！

來源

2017-09-15 06:59:53

<?php 
$ArrayName = array(); 

foreach($records as $record) { 

     $ID = $record->getField('propertyID'); 
     $name = $record->getField('assignedName'); 
     $serialID = $record->getField('serial'); 
     $tagID = $record->getField('tag'); 

$ArrayName[] = array('ID' => $ID, 'name' => $name, 'serialID' => $serialID, 'tagID' => $tagID); //assign each sub-array to the newly created array 

    } 
echo json_encode($ArrayName); 

? 

> Blockquote

來源

2017-09-15 07:00:49 user2686713

這個代碼將幫助您：

<?php 
$resultArray = array(); 

foreach($records as $record) 
{ 
     $newResultArrayItem = array(); 
     $newResultArrayItem['ID'] = $record->getField('propertyID'); 
     $newResultArrayItem['name'] = $record->getField('assignedName'); 
     $newResultArrayItem['serialID'] = $record->getField('serial'); 
     $newResultArrayItem['tagID'] = $record->getField('tag'); 

     $resultArray[] = $newResultArrayItem; 
} 

$encodedArray = json_encode($ArrayName); 

echo $encodedArray; 

?>

來源

2017-09-15 07:35:34

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