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我想改變這個數據,這基本上是從查詢中獲得的。我想將每個部分的數據合併到一個數組中,然後將結果編碼爲json。Php json編碼
Array ([sectionName] => Section C [di] => Robert 2013-10-02 [timeSpent] => 1970,0,1,00,00,06)
Array ([sectionName] => Section C [di] => John 2013-10-09 [timeSpent] => 1970,0,1,02,13,06)
Array ([sectionName] => Section D [di] => Tim 2013-10-03 [timeSpent] => 1970,0,1,00,00,17)
進入
{
"type":"column",
"name":"Section C",
"color":"Highcharts.getOptions().colors[0]",
"data": [{name: Robert 2013-10-02,y:Data.UTC(1970,0,1,00,00,06)},{name: John 2013-10-09,y:Data.UTC(1970,0,1,02,13,06)}]
},
{"type":"column",
"name":"Section C",
"color":"Highcharts.getOptions().colors[1]",
"data":[{name: Tim 2013-10-03,y:Date.UTC(1970,0,1,00,00,17)}]
}
通則
{
type:"column",
name: "SectionName",
color: "Highcharts.getOptions().colors[1]",
data: [{name:di,y:Date.UTC(timeSpent)},{di2 for same section},{di3 etc}]
我已經試過
$i=0;
while($row = db_fetch_array($result)) {
//print_r($row);
$responce[$i][type]='column';
$responce[$i][name]=$row[sectionName];
$responce[$i][color]='Highcharts.getOptions().colors['.$i.']';
$responce[$i][data]=
//the problem comes here where i want to combine data depends on sections
//for each section **di and timeSpent**
'['. array(
name=>$row[di],
y=>'Date.UTC('.$row[timeSpent].')'
).']';
$i++;
}
return json_encode(responce); etc
這是基達詳細說明。我希望你能理解。
我不認爲有任何可用的JSON庫在PHP中,這將幫助你在這裏。你將不得不像你一樣進步 – Sage