PHP Json編碼語法

Question

我是json的新手，並決定使用它，因爲它看起來很有前途。語法如何工作？

這裏是我的簡單的PHP腳本：

$usernames = array('jake', 'john', 'jackie', 'jared'); 
$users = array(); 
for($i = 0; $i < 4; $i++) 
{ 
    $users[$i]['id'] = $i; 
    $users[$i]['name'] = $usernames[i]; 
} 
$data = json_encode($users); 
echo $data; 

它輸出：

{"i":{"id":3,"name":null}} 

我希望它輸出：

[{"id": 1,"name": "jake"},{"id": 2,"name": "john"},{"id": 3,"name": "jackie"},{"id": 4,"name": "jared"}] 

Answer 1

內環路只有一條線路會做

$usernames = array('jake', 'john', 'jackie', 'jared'); 
$users = array(); 
for($i = 0; $i < 4; $i++) 
{ 
    $users[] = array("id"=>$i+1,"name"=>$usernames[$i]); 

} 
$data = json_encode($users); 
echo $data; 

輸出，你在你的問題想

[{"id":1,"name":"jake"},{"id":2,"name":"john"},{"id":3,"name":"jackie"},{"id":4,"name":"jared"}] 

Answer 2

嘗試使用：

$usernames = array('jake', 'john', 'jackie', 'jared'); 
$users = array(); 
foreach($usernames as $id => $username) 
{ 
    $users[$id]['id'] = $id + 1; 
    $users[$id]['name'] = $username; 
} 
$data = json_encode($users); 
echo $data; 

Answer 3

$usernames = array('jake', 'john', 'jackie', 'jared'); 
$users = array(); 
for($i = 0; $i < 4; $i++) 
{ 
    $user=array(); 
    $user['id'] = $i; 
    $user['name'] = $usernames[$i]; 
    $users[]=$user; 
} 
$data = json_encode($users); 
echo $data; 

輸出：

[{"id":0,"name":"jake"},{"id":1,"name":"john"},{"id":2,"name":"jackie"},{"id":3,"name":"jared"}] 

Answer 4

試試這個，

$usernames = array('jake', 'john', 'jackie', 'jared'); 
$users = array(); 
for($i = 0; $i < 4; $i++) 
{ 
    $users[$i]['id'] = $i; 
    $users[$i]['name'] = $usernames[$i]; 
} 
$data = json_encode($users); 
echo $data; 

改變，

$usernames[i] 

要，

$usernames[$i] 

，我認爲它更好地使用foreach循環，而不是爲..

Answer 5

$usernames = array('jake', 'john', 'jackie', 'jared'); 

$users = array(); 

foreach($usernames as $id=>$username{ 
    $id++; 
    $users[]=array('id'=>$id,'name'=>$username); 
} 

$data=json_encode($users);echo $data;