SQL語句中的變量方程式的放置位置？

Question

我正在使用MS Access進行一些計算。下面是給我找麻煩整體代碼：

Dim cmd3 As OleDbCommand = New OleDbCommand("INSERT INTO Criteria (Calculation, [Interval], Tier_Juncture_1, Weight) _ 
SELECT ?, ?, (M * 0) + B _AS Tier_Juncture_1, _ 
((Avg(C." & Calculation & " * G.Growth) - Avg(C." & Calculation & ") * Avg(G.Growth))/(StDevP(C." & Calculation & ") * StDevP(G.Growth)) * 10) AS Weight _ 
FROM (Sum(G.Growth)/Count(*)) - (1 * (Sum(C." & Calculation & ")/Count(*))) AS B, _ 
(Sum(C." & Calculation & " * G.Growth) - ((Sum(C." & Calculation & ") * Sum(G.Growth))/Count(*)))/(Sum(C." & Calculation & " * C." & Calculation & ") - ((Sum(C." & Calculation & ") * Sum(C." & Calculation & ")/Count(*)))) AS M, _ 
" & Calculation & " AS C INNER JOIN " & Growth_Rate & " AS G _ 
" & On_Statement & "", con) 
    cmd3.Parameters.AddWithValue("@Calculation", Calculation) 
    cmd3.Parameters.AddWithValue("@[Interval]", Interval) 
    cmd3.ExecuteNonQuery() 

更具體地講，我的目標是插入這個公式，我的表在現場Tier_Juncture_1命名Criteria結果：

(M * 0) + B _AS Tier_Juncture_1

正如你所看到的，我在這個方程中有兩個變量，M和B。下面是公式的每個：

(Sum(G.Growth)/Count(*)) - (1 * (Sum(C." & Calculation & ")/Count(*))) AS B

(Sum(C." & Calculation & " * G.Growth) - ((Sum(C." & Calculation & ") * Sum(G.Growth))/Count(*)))/(Sum(C." & Calculation & " * C." & Calculation & ") - ((Sum(C." & Calculation & ") * Sum(C." & Calculation & ")/Count(*)))) AS M

我的問題是，凡在我的SQL語句，我把公式爲我的兩個變量SOT我原來的公式Tier_Juncture_1可以使用變量？正如你在上面看到的，我試圖把它們放在我的FROM條款中，但是我得到這個錯誤：Syntax error in FROM clause.

變量本身的公式應該沒有任何問題。我已經獨立測試了它們，並且都返回了正確的值，沒有錯誤。我只需要知道將它們放在我的SQL語句中的位置。

UPDATE

每下面的建議，我從我的SQL語句中刪除的參數。現在看起來是這樣的：

Dim cmd3 As OleDbCommand = New OleDbCommand("INSERT INTO Criteria (Calculation, [Interval], Tier_Juncture_1, Weight) _ 
SELECT " & Calculation & ", " & Interval & ", (M * 0) + B AS Tier_Juncture_1, _ 
((Avg(C." & Calculation & " * G.Growth) - Avg(C." & Calculation & ") * Avg(G.Growth))/(StDevP(C." & Calculation & ") * StDevP(G.Growth)) * 10) AS Weight _ 
FROM (Sum(G.Growth)/Count(*)) - (1 * (Sum(C." & Calculation & ")/Count(*))) AS B, _ 
(Sum(C." & Calculation & " * G.Growth) - ((Sum(C." & Calculation & ") * Sum(G.Growth))/Count(*)))/(Sum(C." & Calculation & " * C." & Calculation & ") - ((Sum(C." & Calculation & ") * Sum(C." & Calculation & ")/Count(*)))) AS M, _ 
" & Calculation & " AS C INNER JOIN " & Growth_Rate & " AS G _ 
" & On_Statement & "", con) 
    cmd3.ExecuteNonQuery() 

但是當我運行此我得到以下錯誤：Syntax error in FROM Clause.

我相信，因爲我插入了我原來的變量方程M和B我得到這個錯誤帖子。所以我的問題依然存在。我在哪裏可以將這些公式放在我的SQL語句中。

月2日更新

這裏是Debug.Writeline(cmd3.CommandText)返回的SQL語句：

INSERT INTO Criteria (Calculation, [Interval], Tier_Juncture_1, Weight) SELECT Current_Ratio, MRQ, (M * 0) + B AS Tier_Juncture_1, ((Avg(C.Current_Ratio * G.Growth) - Avg(C.Current_Ratio) * Avg(G.Growth))/(StDevP(C.Current_Ratio) * StDevP(G.Growth)) * 10) AS Weight FROM (Sum(G.Growth)/Count(*)) - (1 * (Sum(C.Current_Ratio)/Count(*))) AS B, (Sum(C.Current_Ratio * G.Growth) - ((Sum(C.Current_Ratio) * Sum(G.Growth))/Count(*)))/(Sum(C.Current_Ratio * C.Current_Ratio) - ((Sum(C.Current_Ratio) * Sum(C.Current_Ratio)/Count(*)))) AS M, Current_Ratio AS C INNER JOIN Quarterly_Growth_Rates AS G ON (C.Ticker = G.Ticker) AND ((IIF(C.Period = 4, C.Year + 1, C.Year)) = G.Year) AND ((IIF(C.Period = 4, 1, C.Period + 1)) = G.Qtr)

Answer 1

爲了返回非集合領域和聚合函數在SQL，IE Avg(G.Growth)，你必須suply a GROUP BY。

通過查看您的代碼，我知道Calculation不是聚合因爲您使用相同的變量的字段和表名稱。

如果您需要進一步的幫助，您需要提供生成的SQL進行檢查，我們不知道您的變量是什麼。 IE，Debug.Writeline(cmd3.CommandText)