爲什麼我得到下面的代碼

這給出了一個語法錯誤，語法錯誤：爲什麼我得到下面的代碼

import numpy as np 
import scipy.interpolate 
import matplotlib.pyplot as plt 
y = np.array([-0.23122875, -0.11375591, -0.09760733, -0.07401004, -0.03565704,-0.02449268,-0.01411058,0.0018971,-0.0145346,0.00156783,0.0048691,0.01990767,0.02048657,0.01691803,0.02228818,0.02578349,0.02707902,0.01996198]) 
x = np.array(range(len(y))) 
stepsize = 0.0001 
xvals = np.arange(0,13.0001,stepsize) 
func = scipy.interpolate.interp1d(x, y, kind = "cubic") 
yvals = func(xvals) 
plt.plot(xvals,yvals) 
plt.plot(x,y, "o") 
dif = np.diff(yvals) 
for i in range(len(y)) 
    if i == 0: 
     print dif[int(i*1/stepsize)] 
    else: 
     print dif[int(i*1/stepsize)-1]

它給第5行中的語法錯誤，這樣

y = np.array([-0.23122875, -0.11375591, -0.09760733, -0.07401004, -0.03565704,-0.02449268,-0.01411058,0.0018971,-0.0145346,0.00156783,0.0048691,0.01990767,0.02048657,0.01691803,0.02228818,0.02578349,0.02707902,0.01996198]) ^ SyntaxError: invalid syntax

我只是不知道是什麼原因。當我改變y中的某些值時，它突然發揮作用。

在此先感謝

來源

2016-05-19 LMATH

是應該由Python？然後請編輯標籤以包含'python'標籤。另外，當詢問有關錯誤的問題時，包括實際錯誤輸出（完整和未經編輯）通常會有幫助，並指出代碼中錯誤發生的位置。請[閱讀關於如何提出好問題]（http://stackoverflow.com/help/how-to-ask）。 –

你出現在這條線將使用soft hyphen：

y = np.array([-0.23122875, -0.11375591, -0.09760733, -0.07401004, -0.03565704,-0.02449268,-0.01411058,0.0018971,-0.0145346,0.00156783,0.0048691,0.01990767,0.02048657,0.01691803,0.02228818,0.02578349,0.02707902,0.01996198])

你需要將它切換到hyphen-minus這樣的：

y = np.array([-0.23122875, -0.11375591, -0.09760733, -0.07401004, -0.03565704,-0.02449268,-0.01411058,0.0018971,-0.0145346,0.00156783,0.0048691,0.01990767,0.02048657,0.01691803,0.02228818,0.02578349,0.02707902,0.01996198])

來源

2016-05-19 12:19:43 Noelkd

這不是我所期望的語法錯誤。顯示的代碼中還有其他代碼。 :) –

'for'循環。 –

爲什麼我得到下面的代碼

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