1
在R中,str()
便於顯示對象的結構,例如lm()
和其他建模函數返回的列表的列表,但它給出了太多的輸出。我正在尋找一些工具來創建一個簡單的樹形圖,只顯示列表元素及其結構的名稱。生成顯示R對象結構的圖形樹圖
例如,在這個例子中,
data(Prestige, package="car")
out <- lm(prestige ~ income+education+women, data=Prestige)
str(out, max.level=2)
#> List of 12
#> $ coefficients : Named num [1:4] -6.79433 0.00131 4.18664 -0.00891
#> ..- attr(*, "names")= chr [1:4] "(Intercept)" "income" "education" "women"
#> $ residuals : Named num [1:102] 4.58 -9.39 4.69 4.22 8.15 ...
#> ..- attr(*, "names")= chr [1:102] "gov.administrators" "general.managers" "accountants" "purchasing.officers" ...
#> $ effects : Named num [1:102] -472.99 -123.61 -92.61 -2.3 6.83 ...
#> ..- attr(*, "names")= chr [1:102] "(Intercept)" "income" "education" "women" ...
#> $ rank : int 4
#> $ fitted.values: Named num [1:102] 64.2 78.5 58.7 52.6 65.3 ...
#> ..- attr(*, "names")= chr [1:102] "gov.administrators" "general.managers" "accountants" "purchasing.officers" ...
#> $ assign : int [1:4] 0 1 2 3
#> $ qr :List of 5
#> ..$ qr : num [1:102, 1:4] -10.1 0.099 0.099 0.099 0.099 ...
#> .. ..- attr(*, "dimnames")=List of 2
#> .. ..- attr(*, "assign")= int [1:4] 0 1 2 3
#> ..$ qraux: num [1:4] 1.1 1.44 1.06 1.06
#> ..$ pivot: int [1:4] 1 2 3 4
#> ..$ tol : num 1e-07
#> ..$ rank : int 4
#> ..- attr(*, "class")= chr "qr"
#> $ df.residual : int 98
...
我希望得到的東西是這樣的:
這與我從tree
得到的文件夾在我的文件系統:
C:\Dropbox\Documents\images>tree
Folder PATH listing
Volume serial number is 2250-8E6F
C:.
+---cartoons
+---chevaliers
+---icons
+---milestones
+---minard
+---minard-besancon
結果可能是ei在圖形字符中,如tree
或上面顯示的實際圖形。有這樣的東西嗎?
難道你參考這個鏈接https://stackoverflow.com/questions/36094183/how-to-build-從目錄樹樹狀圖? – amrrs
我沒有見過這個。這是一個很好的參考。 – user101089