是否有指定雙精度的數字後綴？

Question

void Foo(float a){} //1 
void Foo(double a){} //2 overloaded 


Foo(1.0f);       //calls function 1 
Foo(1.0 /*double numeric suffix?*/); //calls function 2 

如果不是，是否可以實現這一目標？我主要興趣在 某些操作過程中確保雙精度數學等：在操作過程中

ulong j; 
double v; 

j = /*some value*/; 
if(j>0UL) 
    v = 1.0/j; //if 1.0 is set as a float by the compiler then 
       //could it be likely we lose some precision here 
       //if a double would allow for more precision? Is 
       //a cast the only means of ensuring double precision? 

其他技巧上讓編譯器自動確定類型將是有益的。

Answer 1

C++中不需要後綴。默認情況下，缺少'f'後綴的任何浮點值將被編譯爲編譯器類型double。

參考：http://en.wikipedia.org/wiki/C_0x