分組連續記錄

Question

這是我的記錄（輸入）。所述field2總是開始於100後，它可以採取以上100

field1 field2 
=============== 
val1  100 
val2  110 
------------ 
val3  100 
val4  110 
val3  130 
val3  140 
------------ 
val1  100 

任何值我需要組連續記錄與100開始後，它可以是任何數量不是100對於上面的示例我需要的輸出

field 1     field2 
=================================================== 
(val1, val2)    (100, 110) 
(val3, val4, val3, val3) (100, 110, 130, 140) 
(val1)      (100) 

如何做到這一點

Answer 1

讓我假設你有一個指定排序的列。然後，你可以通過每個記錄之前計數的「100」的記錄數，然後使用array_agg()鑑定組：

select array_agg(field1 order by id) as field1s, 
     array_agg(field2 order by id) as field2s 
from (select t.*, 
      sum(case when field2 = 100 then 1 else 0 end) over (order by id) as grp 
     from t 
    ) t 
group by grp; 

注：在MySQL解決方案看起來非常，非常不同。但是，它仍然會以select開頭。

Answer 2

您必須有一些可用於定義訂單的字段。
在下面的例子，我認爲它是id場

下面應該做你期望

#standardSQL 
SELECT 
    CONCAT('(',STRING_AGG(field1 ORDER BY id), ')') AS field1, 
    CONCAT('(',STRING_AGG(CAST(field2 AS STRING) ORDER BY id), ')') AS field2 
FROM (
    SELECT 
    id, field1, field2, 
    COUNTIF(field2 = 100) OVER (ORDER BY id) AS grp 
    FROM yourTable 
) t 
GROUP BY grp 
ORDER BY MIN(id) 

您可以測試/與嘗試下面的僞數據從你的問題是什麼

#standardSQL 
WITH yourTable AS (
    SELECT 1 AS id, 'val1' AS field1, 100 AS field2 UNION ALL 
    SELECT 2 AS id, 'val2' AS field1, 110 AS field2 UNION ALL 
    SELECT 3 AS id, 'val3' AS field1, 100 AS field2 UNION ALL 
    SELECT 4 AS id, 'val4' AS field1, 110 AS field2 UNION ALL 
    SELECT 5 AS id, 'val3' AS field1, 130 AS field2 UNION ALL 
    SELECT 6 AS id, 'val3' AS field1, 140 AS field2 UNION ALL 
    SELECT 7 AS id, 'val1' AS field1, 100 AS field2 
) 
SELECT 
    CONCAT('(',STRING_AGG(field1 ORDER BY id), ')') AS field1, 
    CONCAT('(',STRING_AGG(CAST(field2 AS STRING) ORDER BY id), ')') AS field2 
FROM (
    SELECT 
    id, field1, field2, 
    COUNTIF(field2 = 100) OVER (ORDER BY id) AS grp 
    FROM yourTable 
) 
GROUP BY grp 
ORDER BY MIN(id) 

輸出爲

field1     field2 
------     ------ 
(val1,val2)    (100,110)  
(val3,val4,val3,val3) (100,110,130,140)  
(val1)     (100)  

想知道如果這是可能的（不使用訂單欄）？

如果你真的有隻在您的表的兩個領域 - 你最有可能的運氣了，需要重新審視與附加字段填入本表的邏輯被用於訂購（作爲時間軸）

作爲一個完全最後的手段 - 你可以嘗試例子飛產生這樣欄下方 - 但請理解也絕對在得到命令，你希望

#standardSQL 
WITH yourTable AS (
    SELECT 'val1' AS field1, 100 AS field2 UNION ALL 
    SELECT 'val2' AS field1, 110 AS field2 UNION ALL 
    SELECT 'val3' AS field1, 100 AS field2 UNION ALL 
    SELECT 'val4' AS field1, 110 AS field2 UNION ALL 
    SELECT 'val3' AS field1, 130 AS field2 UNION ALL 
    SELECT 'val3' AS field1, 140 AS field2 UNION ALL 
    SELECT 'val1' AS field1, 100 AS field2 
), 
tempTable AS (
    SELECT field1, field2, ROW_NUMBER() OVER() AS id 
    FROM yourTable 
) 
SELECT 
    CONCAT('(',STRING_AGG(field1 ORDER BY id), ')') AS field1, 
    CONCAT('(',STRING_AGG(CAST(field2 AS STRING) ORDER BY id), ')') AS field2 
FROM (
    SELECT 
    id, field1, field2, 
    COUNTIF(field2 = 100) OVER (ORDER BY id) AS grp 
    FROM tempTable 
) 
GROUP BY grp 
ORDER BY MIN(id) 

輸出是一樣不能保證 - 但是 - 不能保證在裏面！！！

field1     field2 
------     ------ 
(val1,val2)    (100,110)  
(val3,val4,val3,val3) (100,110,130,140)  
(val1)     (100)