我有一個RSA公共密鑰,使得它看起來像如何從Python的RSA公鑰中提取N和E?
-----BEGIN PUBLIC KEY-----
MIIBIDANBgkqhkiG9w0BAQEFAAOCAQ0AMIIBCAKCAQEAvm0WYXg6mJc5GOWJ+5jk
htbBOe0gyTlujRER++cvKOxbIdg8So3mV1eASEHxqSnp5lGa8R9Pyxz3iaZpBCBB
vDB7Fbbe5koVTmt+K06o96ki1/4NbHGyRVL/x5fFiVuTVfmk+GZNakH5dXDq0fwv
JyVmUtGYAiMJWPni2hGpAsbyjzLix9UNX5XiYIIrIr55IHtD5u1XNkmYLOdVQ98r
6hez3t2eaE0pP2k+mjRach+2tD93PBZmreHgVZtejumi+ZWLMqpd++AY0AzH0m8E
6sa8JFUAiYZbVtmrcGTCUCkzC2Es1/knSeZ41xki1qD0V3uw/APP8Q+BgbX3SJp0
EQIBAw==
-----END PUBLIC KEY-----
我想找出模N和指數E是從這個關鍵,在Python?
使用pycrypto包,我能夠加載到密鑰這樣:
from Crypto.PublicKey import RSA
# read the public key in:
public_key = RSA.importKey(open('key.pub', 'r').read())
但以下pycrypto's rsa module文檔目前還不清楚如何提取更小的組件。我該怎麼做呢?